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aleksandrvk [35]
3 years ago
8

Subtract. 18.754−14.43 0.34 4.324 4.73 33.184

Mathematics
2 answers:
Semmy [17]3 years ago
6 0

Answer:

4.324

Step-by-step explanation:

18.754−14.43 = 4.324

it's best do subtract in standard version (can i have brainliest).

kogti [31]3 years ago
3 0

Answer: SECOND OPTION

Step-by-step explanation:

To subtract the two decimal numbers shown in the problem, you must apply the proccedure shown below:

-  Write the number one under the other, with one decimal point under the other.

- Add a zeros to  14.43 so both have the same length.

- Make the subtraction keeping on mind the decimal point.

Then:

18.754-\\14.430\\----\\4.324

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Elza [17]
8+5i/5+2i
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6 0
3 years ago
Not sure how to solve this
Diano4ka-milaya [45]

Step-by-step explanation:

You just have to plug the numbers they give you into the equation. For the first one, you have 0 + 5y = 10; 5y = 10; y = 2. For the second one, x + 5(0) = 10; x + 0 = 10; x = 10. And lastly, for the third one, x + 5(6) = 10; x + 30 = 10; x = -20.

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3 years ago
Which fraction has a value that's equal to 7/8
S_A_V [24]
There's a bunch of them like if you simplify you could get 3/4.I'll give you some more.

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Hope this helps :D
7 0
3 years ago
Identify an equation in point slope form for the line parallel to y=1/2x-7 that passes through (-3,-2)
ANTONII [103]

Answer:

Step-by-step explanation:

The point slope form of a straight line is expressed as

y - y1 = m(x - x1)

Where

m represents slope of the line

y1 represents the initial value of y

x1 represents the initial value of x

If two lines are parallel, it means that they have the same slope. From the equation of the given line, slope = 1/2

Therefore,

m = 1/2

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Substituting into the point slope equation, it becomes

y - - 2 = 1/2(x - - 3)

y + 2 = 1/2(x + 3)

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4 0
3 years ago
Solve dis attachment and show all work ( I got it all wrong and I want to know how to solve it )
DedPeter [7]
(a) First find the intersections of y=e^{2x-x^2} and y=2:

2=e^{2x-x^2}\implies \ln2=2x-x^2\implies x=1\pm\sqrt{1-\ln2}

So the area of R is given by

\displaystyle\int_{1-\sqrt{1-\ln2}}^{1+\sqrt{1-\ln2}}\left(e^{2x-x^2}-2\right)\,\mathrm dx

If you're not familiar with the error function \mathrm{erf}(x), then you will not be able to find an exact answer. Fortunately, I see this is a question on a calculator based exam, so you can use whatever built-in function you have on your calculator to evaluate the integral. You should get something around 0.5141.

(b) Find the intersections of the line y=1 with y=e^{2x-x^2}.

1=e^{2x-x^2}\implies 0=2x-x^2\implies x=0,x=2

So the area of S is given by

\displaystyle\int_0^{1-\sqrt{1-\ln2}}\left(e^{2x-x^2}-1\right)\,\mathrm dx+\int_{1-\sqrt{1-\ln2}}^{1+\sqrt{1-\ln2}}(2-1)\,\mathrm dx+\int_{1+\sqrt{1-\ln2}}^2\left(e^{2x-x^2}-1\right)\,\mathrm dx
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which is approximately 1.546.

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\displaystyle\pi\int_0^2\left(e^{2x-x^2}-1\right)^2\,\mathrm dx
5 0
3 years ago
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