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seropon [69]
3 years ago
13

Is the classification for an instrument that produces sound whne a string or strings stretched between two points is plucked?

Physics
1 answer:
Yuki888 [10]3 years ago
5 0
The correct answer for the question is Chordophone 
Chordophone is an instrument in which a stretched, vibrating string produces the initial sound. Strings instruments produce sound through the vibration of strings. The length, tightedness, and thickness determines the sound produced by the strings. 
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The Law of Universal Gravitation states that gravity is___ proportional to the product of the two
tekilochka [14]
Gravity is directly proportional to the product of the two. Masses and inversely proportional to the square distance between the two masses.
7 0
4 years ago
Read 2 more answers
How can we measure magnitude of displacement from a v-t curve?​
Ratling [72]

Answer:

The displacement can be calculated by measuring the area of the curve when we move along the t curve. So, that would give the displacement.

Explanation:

4 0
3 years ago
Just before it is struck by a racket, a tennis ball weighing 0.560 N has a velocity of (20.0m/s)ı^−(4.0m/s)ȷ^(20.0m/s)ı^−(4.0m/s
Art [367]

Answer:

(a) Jx = -1.14Ns, Jy = 110×3×10-³ = 0.330Ns (b) V = (0m/s)ı^−(1.79m/s)ȷ^

Explanation:

Given

W = 0.56N = mg

m = 0.56/g = 0.56/9.8 = 0.057kg

t = 3.00ms = 3.00×10-³s

Impulse is a vector quantity so we would treat it as such

We have been given the force and velocity in their component forms so to get the impulse from these quantities, we pick the respective component for the quantity we want to calculate and do the necessary calculation. The masses are scalar quantities and so do not affect the signs used in the calculations whether positive or negative. So we have that

u = (20.0m/s)ı^−(4.0m/s)ȷ^

ux = 20m/s

uy = – 4.0m/s

F = – (380N)ı^+(110N)ȷ^

Fx = –380N

Fy = 110N

J = impulse = force × time = F×t

So Jx = Fx ×t

Jy = Fy×t

Jx = –380×3×10-³ = -1.14Ns

Jy = 110×3×10-³ = 0.330Ns

Impulse also equals the change in momentum of the body. So

J = m(v–u)

J/m = v – u

V= J/m + u

Vx = Jx/m + ux

Vx = –1.14/0.057 + 20

Vx = -20 + 20 = 0m/s

Vx = 0m/s

Vy= Jy/m + uy

Vy= 0.33/0.057 + (-4.0)

Vy= 5.79 + (-4.0) = 1.79m/s

V = (0m/s)ı^−(1.79m/s)ȷ^

5 0
3 years ago
No official standard exists for extinguisher-cylinder colors. that said, a red cylinder is typically associated with which type
Lorico [155]
Fire extinguishers are typically red. Goes along with the red fire trucks and red being a color of emergency. While there isn't any standard, if we decided to change the colors of the fire extinguisher, people would be very confused and given the context, it could cost people's lives, so I'm thinking red will be the color of fire extinguishers for a while to come.
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8 0
4 years ago
An object is traveling at 15 m/s and then after 5 seconds ends up traveling at 10 m/s. Calculate the speeds acceleration rate. W
SSSSS [86.1K]

Answer:

1) a = -1 m/s²

2) v = 12 m/s

Explanation:

Given,

The initial velocity of the object, u = 15 m/s

The final velocity of the object, v = 10 m/s

The time taken by the object to travel is, t = 5 s

Using the first equation of motion

                               <em>v = u + at</em>

                               a = (v - u) / t

Substituting the values

                                a = (10 - 15) / 5

                                    = -1 m/s²

The negative sign indicates the body is decelerating

The acceleration of the object is, a = -1 m/s²

The speed of the object after 2 seconds

From the above equations of motion

                                  v = 15 + (-1) 2

                                     = 12 m/s

Hence, the speed of the object after 2 seconds is, v = 12 m/s

7 0
4 years ago
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