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2 years ago

13

A(n) ______ can act as an electronic switch that opens or closes the circuits for electrical charges.

1 answer:

uysha [10]2 years ago

8 0

Answer: diode

Explanation: A diode is an electronic device that has the ability to work in 1 direction of electric current.

At forward bias ( when the positive terminal of the diode is connected to the positive terminal of the source and negative terminal to the negative of the source) the diode allows current to flow thus acting as a close switch.

At reverse bias ( when the positive terminal of the diode is connected to the negative terminal of the source and the negative terminal of the diode to the positive terminal of the source) the diode stops question from flowing thus acting like an open circuit or an open switch

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Carbon dioxide, nitrous oxide, methane and ozone are all greenhouse gases.

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Jose is loading his luggage into his car so that he can go to visit his grandmother. He lifts his suitcase up a 10 m staircase i

maxonik [38]

Answer:

The work done on the suitcase is, W = 600 J

Explanation:

Given,

The average force exerted by Jose on his suitcase, F = 60 N

Jose carried the suitcase to a distance, S = 10 m

The work done on the suitcase is given by the relation

<em>W = F x S</em>

Substituting the given values in the above equation,

W = 60 N x 10 m

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2 years ago

The speed of sound in room temperature (20°C) air is 343 m/s; in room temperature helium, it is 1010 m/s. The fundamental freque

Lera25 [3.4K]

Answer: f = 927.55Hz

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L = λ/4 where λ = wavelength.

speed of sound in air = v = 343m/s.

fundamental frequency of open closed tube = 315Hz

λ = 4L.

v = fλ

343 = 315 * 4L

343 = 1260 * L

L = 343/ 1260

L = 0.27m

In the same tube of length L = 0.27m but different medium ( helium), the speed of sound is 1010m/s.

The length of tube and wavelength are related by the formulae below

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λ = 1.087m.

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2 years ago

a particle of mass m sits at rest at x = 0. At time t = 0 a force given by F = Fe^(-t/T) is applied in the +x direction; F and T

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Explanation:

Given: $F=m\ddot{x}=Fe^{-\frac{t}{T}}$

Solving for $\ddot{x}$ :

$\ddot{x}=\frac{F}{m}e^{-\sqrt{\frac{F}{m} } t}$

where:

$T=\sqrt{\frac{m}{F}}$

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$\dot{x}=\sqrt{\frac{F}{m}}-\sqrt{\frac{F}{m}} e^{-\sqrt{\frac{F}{m}} t}$

Integrating to get x with initial conditions x(0) = 0:

$x=-1+\sqrt{\frac{F}{m}} t+e^{-\sqrt{\frac{F}{m}}t}$

When t=T:

$x=-1+\sqrt{\frac{F}{m}}\sqrt{\frac{m}{F}}+e^{-\sqrt{\frac{F}{m}}\sqrt{\frac{m}{F}}}=\frac{1}{e}$

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