The momentum, p, of any object having mass m and the velocity v is

Let
and
be the masses of the large truck and the car respectively, and
and V_S be the velocities of the large truck and the car respectively.
So, by using equation (i),
the momentum of the large truck 
and the momentum of the small car
.
If the large truck has the same momentum as a small car, then the condition is

The equation (ii) can be rearranged as

So, the first scenario:


So, to have the same momentum, the ratio of mass of truck to the mass of the car must be equal to the ratio of velocity of the car to the velocity of the truck.
The other scenario:


So, to have the same momentum, the ratio of mass of truck to the velocity of the car must be equal to the ratio of mass of the car to the velocity of the truck.
Force = 0.20N .F = m ×a .& a = v/t then the f = m×v/t
<u>Answer:</u>
Cannonball will be in flight before it hits the ground for 2.02 seconds
<u>Explanation:</u>
Initial height from ground = 20 meter.
We have equation of motion ,
, s is the displacement, u is the initial velocity, a is the acceleration and t is the time.
In this the velocity of body in vertical direction = 0 m/s, acceleration = 9.8
, we need to calculate time when s = 20 meter.
Substituting

So it will take 2.02 seconds to reach ground.
<span>The physical feel of H2O is the same regardless of the sample size of the substance. Water feels wet whether it is a single drop or equivalent in volume to an ocean. It is the way the substance feels no matter how much or how little there is present.</span>