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2 years ago

Match the following examples of energy with the primary form of energy exhibited.

Physics

2 answers:

Travka [436]2 years ago

8 0

Answer:

• Friction ( heat )

• Nuclear power plant ( nuclear )

• Toaster element ( heat )

• welding torch ( heat )

• eraser sitting on a desk edge (potential)

• light bulb ( light )

• campfire ( heat )

• moving car ( kinetic )

• lump of coal in a storage bin ( potential )

• stick of tent ( potential)

Explanation: hope this helps !

GalinKa [24]2 years ago

3 0

The primary energy exhibited is:

friction: Heat energy

Due to friction. there is heat loss in mostly all machines.

nuclear power plant: Nuclear energy

In nuclear power plant, fission or fusion of radio-active substances produces large amount of nuclear energy.

toaster element: Heat energy

Heat energy is produced in the toaster when electricity passes through the element. This is used to heat the toasts.

welding torch: Heat energy

The heat energy produced in the welding torch is used in welding.

eraser sitting on a desk edge: Potential energy

Potential energy is possessed by a body due to virtue of its height.

light bulb: Heat energy and light energy.

The element inside the bulb gets heated first and then light energy is produced.

campfire: Heat energy

Heat is produced and then light energy in case of campfire.

moving car: Kinetic energy

A moving body has kinetic energy.

lump of coal in a storage bin: Potential energy

A lump of coal in a storage bin has potential energy.

stick of TNT: potential energy

Stick of TNT is formed of explosive mixture. It contains potential energy.

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Find the acceleration of the blocks when the system is released. The coefficient of kinetic friction is 0.4, and the mass of eac

grin007 [14]

Answer:

a = 4.9(1 - sinθ - 0.4cosθ)

Explanation:

Really not possible without a complete setup.

I will ASSUME that this an Atwood machine with two masses (m) connected by an ideal rope passing over an ideal pulley. One mass hangs freely and the other is on a slope of angle θ to the horizontal with coefficient of friction μ. Gravity is g

F = ma

mg - mgsinθ - μmgcosθ = (m + m)a

mg(1 - sinθ - μcosθ) = 2ma

½g(1 - sinθ - μcosθ) = a

maximum acceleration is about 2.94 m/s² when θ = 0

acceleration will be zero when θ is greater than about 46.4°

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3 years ago

Earth is like a bar magnet. What does this mean about its magnetic poles?

Anit [1.1K]

B a bar magnet has a north and a south pole.

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3 years ago

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Imagine how mercury might be different if it had the same mass as earth. Explain.

maxonik [38]

I believe if it were heavier with more mass, then the sun would pull it in and there would be no mercury. It might also be hotter.

4 0

3 years ago

A seagull flying horizontally at 8.00m/s carries a clam with a mass of 300g in its beak. Calculate the total mechanical energy o

Stells [14]

Answer:

9.6J+88.2J=97.8J

Explanation:

Here the velocity of the seagull is given,mass is given and its height.

We have to find its mechanical energy my friend.

Mechanical energy=kinetic energy + potential energy.

First we will find kinetic energy.

For calculating kinetic energy we need mass and velocity,which are given here.

So, Ek=

$1 \div 2mv {?}^{2}$

So by substituting the values we get 9.6J.

Now we find the potential energy which is mgh.

By substituting the values we get 88.2J.

Then we add both of those and get 97.8J

I hope this satisfies you and make sure you contact me if it doesn't

7 0

3 years ago

A proton moving at 3.90 106 m/s through a magnetic field of magnitude 1.80 T experiences a magnetic force of magnitude 7.20 10-1

VARVARA [1.3K]

Answer:

$\theta=40^0$

Explanation:

The magnitude of the magnetic force is

$F_m=evB\sin\theta$

To find the angle, we make $\sin\theta$ subject of the formula

$\implies \sin\theta=\frac{F_m}{evB}=\frac{7.20\times 10^{-13}}{1.6\times 10^{-19}\times 3.90\times 10^6\times 1.80}$

$\implies \sin\theta=0.641025641$

$\therefore \theta=\sin^{-1}=39.8683^0\\\implies \theta\approxeq 40^0$

8 0

3 years ago