Answer : The value of equilibrium constant (K) is, 0.004
Explanation :
First we have to calculate the concentration of 

and,

Now we have to calculate the value of equilibrium constant (K).
The given chemical reaction is:

Initial conc. 1.2 0 0
At eqm. (1.2-2x) 2x x
As we are given:
Concentration of
at equilibrium = x = 0.1 M
The expression for equilibrium constant is:
![K_c=\frac{[SO_2]^2[O_2]}{[SO_3]^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BSO_2%5D%5E2%5BO_2%5D%7D%7B%5BSO_3%5D%5E2%7D)
Now put all the given values in this expression, we get:



Thus, the value of equilibrium constant (K) is, 0.004
Water is H2O, whereas Hydrogen Peroxide is H2O2 -> the extra oxygen atom changes the substance entirely.
My part of the atom, I'm guessing you are referring to the protons, neutrons, and electrons.
The smallest of these three is the electron.
It would be an opinion because she doesn't exactly know what happened.