Answer is: 5.22·10²² atoms of Iodine.
m(CaI₂) = 12.75 g; mass of calcium iodide.
M(CaI₂) = 293.9 g/mol; molar mass of calcium iodide.
n(CaI₂) = m(CaI₂) ÷ M(CaI₂).
n(CaI₂) = 12.75 g ÷ 293.9 g/mol.
n(CaI₂) = 0.043 mol; amount of calcium iodide.
In one molecule of calcium iodide, there are two iodine atoms
n(I) = 2 · n(CaI₂).
n(I) = 0.086 mol; amount of iodine atoms.
Na = 6.022·10²³ 1/mol; Avogadro number.
N(I) = n(I) · Na.
N(I) = 0.086 mol · 6.022·10²³ 1/mol.
N(I) = 5.22·10²²; number of iodine atoms.
Answer:
160.3 g S
Explanation: there you go
Density = mass/volume
so rearranged mass = volume x density
mass = 8.920 x 45 = 401.4g
rearrange (there are 1000grams in 1kg)
volume = mass/density
volume = 1000/8.920
volume = 112.1076233cm3
The conditions of temperature and pressure in which a gas least soluble in water is low pressure and high temperature.
<h3>What is Henry Law?</h3>
The amount of dissolved gas in a liquid is proportional to its partial pressure above the liquid, according to Henry's law.
From this law it is clear that:
- As the pressure of the gas increases solubility of the gas on the liquid also increases.
But if the temperature of the liquid decreases then the solubility of the gas also increases.
Hence at low pressure and high temperature, gas is least soluble.
To know more about solubility of gas, visit the below link:
brainly.com/question/14747303
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