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Dvinal [7]
3 years ago
11

A sample of natural rubber (200.0 g) is vulcanized, with the complete consumption of 4.8 g of sulfur. Natural rubber is a polyme

r of isoprene (C5H8). Four sulfur atoms are used in each crosslink connection. What percent of the isoprene units will be crosslinked
Chemistry
1 answer:
nasty-shy [4]3 years ago
3 0

Answer: 1.3% many crosslinks as isoprene units,  

Explanation:

Given:

mass pf natural rubber= 200.0g

mass of sulphur = 4.8g

molar mass of sulphur =32g/mol

molar mass of isoprene = C5H8=( 12x5) +(1x8)= 68g/mol

Solution: we first find no of moles present in each  using

no of moles = \frac{mass}{molarmass}

Isoprene: 200.0g x [1mole / 68g] = 2.94moles.

Sulfur: 4.8g x [1mole / 32g] x [1 mole crosslinks / 4 moles S] = 0.0375 moles crosslinks.

to find % crosslinked units, we have  

0.0375 / 2.94 = 1.3% as many crosslinks as isoprene units,  

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Match the description with either a dehydration reaction or a hydrolysis reaction.
Gelneren [198K]

Answer:

1) Hydrolysis

2)Dehydration

3)Dehydration

4)Hydrolysis

Explanation:

Hydrolysis is the chemical breakdown of substances by water and depends on the chemistry, solubility, pH, and the oxidation–reduction (Eh or redox) potential of compound

<em>https://www.sciencedirect.com/topics/earth-and-planetary-sciences/hydrolysis</em>

With hydrolysis water will be a reactant, not a product, and is associated with breaking down substances. Hence 1 and 4 being a Hydrolysis reaction.

Dehydration on the other hand, is defined as :

In a dehydration reaction, either a hydroxyl group from one molecule combines with a hydrogen atom from the other molecule, or two hydrogen atoms from one molecule combine with an oxygen atom on the other molecule. In either case, water is released, and the two molecules are joined together.

https://www.albert.io/blog/dehydration-synthesis-ap-biology-crash-course/

Therefore it is associated with creating a bond of sorts, and water is a product, which is why 2 and 3 are dehydration.

Hope this helps!

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3 years ago
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What is the volume of 15.2 grams of SO2 at STP?
kiruha [24]

5.512 litres is the volume of  15.2 grams of sulphur dioxide gas at STP.

Explanation:

Data given:

mass of sulphur dioxide = 15.2 grams

conditions is at STP whech means volume = 22.4 litres

atomic mass of sulphur dioxide = 64.06 grams/mole

Number of moles is calculated as:

number of moles = \frac{mas}{atomic mass of 1 mole}

Putting the values in the equation:

number of moles = \frac{15.2}{64.06}

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Assuming that sulphur dioxide behaves as an ideal gas, we can calculate the volume as:

When 1 mole of sulphur dioxide occupies 22.4 litres at STP

Then 0.23 moles of sulphur dioxide occupies 22.4 x 0.23

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