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Dahasolnce [82]
3 years ago
9

I need a sentence using dune fence

Chemistry
2 answers:
Mama L [17]3 years ago
8 0
Let's build a dune fence, and let Mexico pay for it. ( ̄ェ ̄;)
Andreyy893 years ago
5 0
Google has lots of answers for ex; Me and a bunch of friends climbed the dune fence as we were tryna escape.
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What can be said about the spontaneity of this reaction? cdiamond→cgraphite
anastassius [24]
The gibbs free energy of the reaction of diamond to graphite is equal to -2.90 kJ/mol. The free energy is negative which means that the reaction is spontaneous. Therefore, the forward reaction is favored. Hope this helps. Have a nice day.
7 0
2 years ago
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A generator does work on an electric heater by forcing an electric current through it. Suppose 1 kJ of work is done on the heate
azamat

Answer:

The change in internal energy of the heater is 0 kJ

Explanation:

∆U = Q - W

Q is quantity of heat transferred = 1 kJ

W is work done on the heater = 1 kJ

Change in internal energy (∆U) = 1 - 1 = 0 kJ

3 0
3 years ago
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What percentage of children who are raised in abusive households grow up to be abusive parents themselves?
Gwar [14]
33%, according to Quizlet

8 0
3 years ago
Determine the mass of each sample 1.55 kmol sulfur trioxide
xxMikexx [17]

Explanation:

Given parameters:

Number of moles of the sulfur trioxide = 1.55kmol = 1.55 x 10³mole

Unknown:

Mass of the sulfur trioxide = ?

Solution:

To solve for the mass of the sample of sulfur trioxide:

  •  Find the molar mass of the compound i.e SO₃

          atomic mass of S = 32g

                                    O = 16g

              molar mass = 32 + 3(16) = 80g/mol

  • Use the formula below:

           mass of SO₃ = number of moles x molar mass

           mass of SO₃ =  1.55 x 10³ x 80 = 124000g or 124kg

Learn more:

mole calculation  brainly.com/question/13064292

#learnwithBrainly

3 0
3 years ago
Determine the number of moles of air present in 1.35 L at 760 torr and 17.0 C. Which equation should you use?
Vanyuwa [196]

C. N = PV/RT is the anwser to your question

4 0
3 years ago
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