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creativ13 [48]
3 years ago
5

In the triangle below, what is csc θ?

Mathematics
2 answers:
earnstyle [38]3 years ago
8 0
It si cool so basicly u take 5 divide bye 13 times 5

MaRussiya [10]3 years ago
7 0
I hope this helps you



csc(theta)=1/sin(theta)



sin(theta)=height/hypothenus



sin(theta)=5/13


csc(theta)=1/5/13


csc(theta)=13/5=2.6
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Answer:

x = 0.5

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Step-by-step explanation:

x + 6y = 2

3x + 2y = 10

Multiply a number by any of the equations to get numbers of the same variable

3x + 18y = 6

3x + 2y = 10

3x - 3x = 0

NB: subtract evenly if u subtract down from top make sure u subtract down from top throughout

16y = -4

16y/16 = -4/16

y = -1/4 or -0.25

to find the x value, any where you see y u put in the y value(-0.25)

So u'll pick just one of the equations above

x + 6(0.25) = 2

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3 years ago
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Elina [12.6K]

Answer:

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4 0
3 years ago
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Given: △ABC, m∠A=60° m∠C=45°, AB=8 Find: Perimeter of △ABC, Area of △ABC
jarptica [38.1K]

We are given

△ABC, m∠A=60° m∠C=45°, AB=8

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we know that sum of all angles is 180

m∠A+ m∠B+m∠C=180

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60°+ m∠B+45°=180

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we can use law of sines

\frac{AB}{sin(C)}=\frac{BC}{sin(A)}

now, we can plug values

\frac{8}{sin(45)}=\frac{BC}{sin(60)}

BC=\frac{8}{sin(45)} \times sin(60)

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\frac{AB}{sin(C)}=\frac{AC}{sin(B)}

now, we can plug values

\frac{8}{sin(45)}=\frac{AC}{sin(75)}

AC=\frac{8}{sin(45)} \times sin(75)

AC=10.928

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p=AB+BC+AC

we can plug values

p=10.928+8+9.798

p=28.726

Area:

we can use formula

A=\frac{1}{2}AB \times AC \times sin(A)

now, we can plug values

A=\frac{1}{2}8 \times 10.928 \times sin(60)

A=37.85570...............Answer

6 0
4 years ago
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