4 1/3 ÷ 5 1/6 the respricol of a fraction must be found to solve the problem .what is reciprocal fraction that should be used ?

In Middletown, Main Street and Market Street are parallel to each other. Patrick Street intersects Market Street to form a 76° a

OLga [1]

Answer:

e

Step-by-step explanation:

8 0

3 years ago

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Write the expression in repeated multiplication form. Then write the expression as a power. (-8)^3*(-8)^4 The expression in repe

Makovka662 [10]

Given:

The expression is

$(-8)^3\cdot (-8)^4$

To find:

The expression in repeated multiplication form and then write the expression as a power.

Solution:

We have,

$(-8)^3\cdot (-8)^4$

The repeated multiplication form of this expression is

$=[(-8)\cdot (-8)\cdot (-8)]\cdot [(-8)\cdot (-8)\cdot (-8)\cdot (-8)]$

$=(-8)\cdot (-8)\cdot (-8)\cdot (-8)\cdot (-8)\cdot (-8)\cdot (-8)$

Clearly, (-8) is multiplied seven times by itself. So,

$=(-8)^7$

Therefore, the repeated multiplication form of the given expression is $(-8)\cdot (-8)\cdot (-8)\cdot (-8)\cdot (-8)\cdot (-8)\cdot (-8)$ and the expression as single power is $(-8)^7$ .

7 0

3 years ago

Show that the line 4y = 5x-10 is perpendicular to the line 5y + 4x = 35

Shkiper50 [21]

Step-by-step explanation:

<h2><em><u>concept :</u></em></h2><h2 /><h2><em><u>concept :When two lines are perpendicular, then the product of their slopes is equivalent to -1.</u></em></h2><h2 /><h2><em><u>concept :When two lines are perpendicular, then the product of their slopes is equivalent to -1.Equation of line in the form y = mx + c have m as slope of line and c as y-intercept.</u></em></h2><h2 /><h2><em><u>concept :When two lines are perpendicular, then the product of their slopes is equivalent to -1.Equation of line in the form y = mx + c have m as slope of line and c as y-intercept.Solution:</u></em></h2><h2 /><h2><em><u>concept :When two lines are perpendicular, then the product of their slopes is equivalent to -1.Equation of line in the form y = mx + c have m as slope of line and c as y-intercept.Solution:Given equations of lines are</u></em></h2><h2 /><h2><em><u>concept :When two lines are perpendicular, then the product of their slopes is equivalent to -1.Equation of line in the form y = mx + c have m as slope of line and c as y-intercept.Solution:Given equations of lines are4y = 5x-10</u></em></h2><h2 /><h2><em><u>concept :When two lines are perpendicular, then the product of their slopes is equivalent to -1.Equation of line in the form y = mx + c have m as slope of line and c as y-intercept.Solution:Given equations of lines are4y = 5x-10or, y = (5/4)x(5/2).</u></em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>(</em><em>1</em><em>)</em></h2><h2 /><h2><em><u>5y + 4x = 35</u></em></h2><h2 /><h2><em><u>5y + 4x = 35ory = (-4/5)x + 7.</u></em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>(</em><em>2</em><em>)</em></h2><h2 /><h2><em><u>Let m and n be the slope of equations i and ii, respectively.</u></em></h2><h2 /><h2><em><u>Let m and n be the slope of equations i and ii, respectively.Here, m = 5/4</u></em></h2><h2 /><h2><em><u>Let m and n be the slope of equations i and ii, respectively.Here, m = 5/4n= -4/5</u></em></h2><h2 /><h2><em><u>Let m and n be the slope of equations i and ii, respectively.Here, m = 5/4n= -4/5therefore, mx n = -1</u></em></h2><h2 /><h2><em><u>Let m and n be the slope of equations i and ii, respectively.Here, m = 5/4n= -4/5therefore, mx n = -1Hence, the lines are perpendicular.</u></em></h2>

8 0

3 years ago

Which value of x makes 7+5(x-3)=227+5(x−3)=22 a true statement?

Greeley [361]

Answer: Your input has more than one equals sign.

Step-by-step explanation:

6 0

3 years ago

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How do you know if a fraction is equal to one?

NeTakaya

You would know because for example, if it's out of 4 and the fraction said 4/4, that would mean one. 3/3 would mean one. 2/2 and so on