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DIA [1.3K]
3 years ago
12

If two runners take the same amount of time to run a mile, they have the same __________.

Physics
2 answers:
vredina [299]3 years ago
8 0

The answer is Velocity. I just took the test. Good luck everyone!

Elan Coil [88]3 years ago
3 0

None of the choices is correct.

If two runners take the same amount of time to run a mile,
they have the same average speed.  But their velocities
are not the same unless both runners begin and end their
run at the same points.

Speed is   (distance covered) divided by (time to cover the distance).

Velocity is not.  It's something different. 
'Velocity' is not just a bigger word for 'speed'.

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The gage pressure of an automobile tire is measured to be 210kPa before a trip and 220kPa after the trip at a location where the
Katarina [22]

Answer:

T_{f} = 312.348\,K\,(39.198\,K)

Explanation:

Let assume that gas inside the automobile tire behaves as an ideal gas. Due to the absence of leakages, the number of moles remains constant during the trip. Air temperature can be found by using the following relation:

\frac{P_{o}}{T_{o}}=\frac{P_{f}}{T_{f}}

Final temperature is cleared with the expression:

T_{f} = \frac{P_{f}}{P_{o}}\cdot T_{o}

T_{f} = \frac{220\,kPa}{210\,kPa}\cdot (298.15\,K)

T_{f} = 312.348\,K\,(39.198\,K)

7 0
3 years ago
What is the momentum of an object with mass 8 kg and velocity 5 m/s
Slav-nsk [51]

Momentum = (mass) x (speed)

Momentum = (8 kg) x (5 m/s)

Momentum = 40 kg-m/s

6 0
3 years ago
What is the wavelength of visible light emitted at 4.2 x 10^8 Answer in units of M
Ber [7]

Answer:

0.714 m

Explanation:

From the question,

v = λf......................... Equation 1

Where v = velocity of visible light, f = frequency of visible light, λ = wave length of visible light.

make λ the subject of the equation

λ = v/f.................. Equation 2

Given: f = 4.2×10⁸ Hz

Note: Light is an electromagnetic wave, and all electromagnetic waves travels with the same speed (3×10⁸ m/s)

Constant: v = 3×10⁸ m/s

Substitute these values into equation 2

λ = 3×10⁸/4.2×10⁸

λ = 0.714 m

8 0
3 years ago
Find the acceleration of the system and the tension in the ropes for the system shown. The table mass is 30 kg and the hanging m
marusya05 [52]

The system's tension is 616 N and acceleration is 5.6 m / s^{2}

<u>Explanation:</u>

From newton’s second law of motion which state that net force acting on a body is product of mass of a body and acceleration of a body which is given as,

             F_{n e t}=m_{t o t} \times a

Where,

F_{n e t} is net force acting on body

m_{\mathrm{tot}} is mass of body

a is acceleration of body

Given values  

Table mass (m) = 30 kg

Hanging mass (m) = 40 kg

                a=\frac{F_{n e t}}{m_{\mathrm{tot}}}=\frac{m \times g}{m_{\mathrm{tot}}}

Put the value for m = hanging mass = 40 kg and g=9.8 \mathrm{m} / \mathrm{s}^{2}, we get

                  a=\frac{40 \times 9.8}{30+40}=\frac{392}{70}=5.6 \mathrm{m} / \mathrm{s}^{2}

The tension in the ropes,  T=(m \times g)+(m \times a)

Here, m as hanging mass

T = tension, N or  k g m / s^{2}

m = mass, kg  

g = gravitational force, 9.8 \mathrm{m} / \mathrm{s}^{2}

a = acceleration, m / s^{2}

          T = (40 \times 9.8)+(40 \times 5.6) = 392+224 = 616 N

3 0
3 years ago
How does a machine, such as a ramp, help make work easier?
Dovator [93]

Answer:

D

A machine can help decrease the input force and increase the output force.

6 0
2 years ago
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