Part 1- The work done by the gas during this process will be 5.65 ×10⁻³ kJ.
Part 2-The heat added to the gas during this process will be 5.65 ×10×10⁻³ kJ.
<h3>What is work done by the gas?</h3>Work is the product of pressure p and volumes V during a volume change for such a gas. The work seems to be the area under the curve that indicates how the state changes.
The work done under the isothermal process is;
For the isothermal process;
ΔU=0
Hence, the work done, and the heat added by the gas during this process will be 5.65 ×10⁻³ kJ and 5.65 ×10×10⁻³ kJ respectively.
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