Answer:
the light creates sorta a mixture of all the colors on the white index card.
Answer:
A. 0.25 A
B. 4.5 V
Explanation:
A. The total resistance of resistances in series is:
R = R₁ + R₂
R = 18 Ω + 18 Ω
R = 36 Ω
Ohm's law:
V = IR
9 V = I (36 Ω)
I = 0.25 A
B. The voltage across the bulb (between P and the battery) can be found with Ohm's law.
V = IR
V = (0.25 A) (18 Ω)
V = 4.5 V
Answer: El trabajo realizado al desplazar el bloque es: 75 N.m
Datos:
Fuerza= F= 25 N
Distancia= d= 3 m
Explicación:
El trabajo es el producto de la fuerza ejercida sobre un cuerpo con el desplazamiento producido por la fuerza. Para que exista trabajo, la dirección de la fuerza debe ser igual a la dirección del desplazamiento.
Trabajo= Fuerza x Desplazamiento
Reemplazando los datos:
T= 25 N * 3 m
T= 75 N.m
Initial velocity of object vi=10.0 cm/s
initial position fo vector of the object is xi=3.09 cm
Final position of vector xf=-5.00cm
then displacement of object s = xf-xi=-5.00-3.09=-8.09cm
time t=2.55 s
s=vit+1/2at2
-5.00 = 11*2.55+1/2*a2.552
a = (-5.00 - 10*2.55*2)/2.552 = 2.94 cm
Acceleration is 2.94 cm.
<h3>What is a
cceleration?</h3>
Speed increase is the name we provide for any cycle where the speed changes. Since speed is a speed and a bearing, there are simply two different ways for you to speed up: change your speed or shift your course or change both. In mechanics, speed increase is the pace of progress of the speed of an item concerning time. Speed increases are vector amounts. The direction of an item's speed increase is given by the direction of the net power following up on that article. An item's typical speed increase throughout some stretch of time is its adjustment of speed separated by the term of the period. Numerically, quick speed increase, in the meantime, is the constraint of the typical speed increase over a little time period. In the terms of analytics, immediate speed increase is the subordinate of the speed vector concerning time.
Learn more about acceleration, refer:
brainly.com/question/27973611
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Answer: The time required for the impluse passing through each other is approximately 0.18seconds
Explanation:
Given:
Length,L = 50m
M/L = 0.020kg/m
FA = 5.7×10^2N
FB = 2.5×10^2N
The sum of distance travelled by each pulse must be 50m since each pulse started from opposite ends.
Ca(t) + CB(t) = 50
Where CA and CB are the velocities of the wire A and B
t = 50/ (CA + CB)
But C = Sqrt(FL/M)
Substituting gives:
t = 50/ (Sqrt( FAL/M) + Sqrt(FBL/M))
t = 50/(Sqrt 5.7×10^2/0.02) + (Sqrt(2.5×10^2/0.02))
t = 50 / (168.62 + 111.83)
t = 50/280.15
t = 0.18 seconds
