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2 years ago

Solve this chemical equation: CH3CH2OH+O2=CO2+H2O

Physics

1 answer:

masha68 [24]2 years ago

4 0

Answer:

some kind of chemical of which i do not know

Explanation:

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A bicyclist is riding a constant speed 62.0 seconds for 200. meters what is his average speed

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2 years ago

ANSWER One end of a string is attached to an object of mass M, and the other end of the string is secured so that the object is

qaws [65]

Answer:

Explanation:

It is a case of oscillation by simple pendulum . Expression for simple pendulum is given as follows

T = $2\pi\sqrt{\frac{l}{g} }$

where T is time period , l is length of pendulum and g is acceleration due to gravity .

$\frac{1}{f} =2\pi\sqrt{\frac{l}{g} }$ , f is frequency of oscillation

For the given case

$\frac{1}{f_o} =2\pi\sqrt{\frac{l}{g} }$

subsequently length becomes half so

$\frac{1}{f} =2\pi\sqrt{\frac{l}{2g} }$

dividing

$\frac{f}{f_o} = \sqrt{\frac{2}{1} }$

f = $\sqrt{2} f_o$

frequency of oscillation becomes √2 times.

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3 years ago

Which of the following statements regarding orbits is true?

Damm [24]

Answer:

the orbit of the a planet has an elliptical shape with the sun at the focus

Explanation:

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3 years ago

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Marta_Voda [28]

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3 years ago

A spring of negligible mass has force constant of 1600 Newtons per meter. (a) How far must the spring be compressed for 3.20 Jou

frez [133]

Answer:

a) x=63.0 $x10^{-3} m$ or 6.3cm

b) x=116.0 $x10^{-3} m$ or 11.6cm

Explanation:

a).

The elastic potential energy is modeling by equation :

$U1=\frac{1}{2}*k*x^{2} \\K=1600 \frac{N}{m}\\ U=3.2J\\m=1.2kg\\x^{2}=\frac{2*U}{k}\\x=\sqrt{\frac{2*3.2J}{1600 \frac{N}{m}}} \\x=\sqrt{4x10^{-3} m^{2}}\\ x=0.06324m$

b).

The work energy theorem explain which work is done in this case. the motion began from the rest so K1=K2 equal zero, Ug1 is no yet done and U2is also zero because is the potential energy

$Ug=K2\\mgy=\frac{1}{2}*k*x^{2} \\but \\y=h+x=0.80m+x\\m*g*(0.80m+x)=\frac{1}{2}*k*x^{2}$

Solving for x

$2*(m*g(h+x))=k*x^{2} \\k*x^{2}-(2*m*g*x)-(2*m*g*h)=0\\1600x^{2} -2*1.2kg*9.8\frac{m}{s^{2}}*x-2*1.2kg*0.80m=0\\1600x^{2} -23.52x-18.816m=0$

$x=-\frac{b+/-\sqrt{b^{2}-4*a*c } }{2*a} \\x=-\frac{-23.52+/-\sqrt{-23.52^{2}-4*1600*-18.816 } }{2*a} \\x=11.79 +/- 173.9\\x1=-0.10 m\\x2=0.116$

The negative is discard so

x=0.116m

7 0

3 years ago

Solve this chemical equation: CH3CH2OH+__O2=CO2+__H2O

Solve this chemical equation: CH3CH2OH+O2=CO2+H2O