Solve this chemical equation: CH3CH2OH+__O2=CO2+_

Un automovil parte del reposo y acelera uniformemente hasta alcanzar una rapidez de 0,255km/h en un tiempo de 3/4 Minutos determ

Elden [556K]

Answer:

a = 1.5*10^-3 m/s^2

x = 0.033m = 3.3cm

Explanation:

To calculate the acceleration and the distance traveled by the car you use the following formulas:

$v=v_o+at$ (1)

$x=v_ot+\frac{1}{2}at^2$ (2)

v: final velocity = 0,255 km/h

vo: initial velocity = 0 m/s

t: time = 3/4 min

a: acceleration = ?

x: distance

In order to use the equations (1) and (2) you first convert the units of the final velocity to m/s, and the time to seconds.

$v=0,255\frac{km}{h}*\frac{1000m}{1km}*\frac{1h}{3600s}\\\\v=0.07m/s\\\\t=\frac{3}{4}min*\frac{60s}{1min}=45s$

Next, you solve the equation (1) for the acceleration a:

$a=\frac{v}{t}=\frac{0.07m/s}{45s}=1.5*10^{-3}\frac{m}{s^2}$

With this value of a you can calculate the distance traveled by the car, by using the equation (2):

$x=\frac{1}{2}(1.5*10^{-3}m/s^2)(45s)^2=0.033m=3.3cm$

hence, the acceleration of the car is 1.5*10^-3 m/s^2 and the distance traveled in 3/4 min is 0.033m

5 0

4 years ago

A physics professor wants to perform a lecture demonstration of Young's double-slit experiment for her class using the 633-nm li

babunello [35]

Answer:

0.00001266 m

Explanation:

D = Distance from source to screen

m = Order

d = Slit separation

The distance from a point on the screen to the center line

$y=\frac{m\lambda D}{d}$

At m = 0

$y_0=0$

$y_1-y_0=35\ cm\\\Rightarrow y_1=35\ cm$

At m = 1

$y_1=\frac{1\times 633\times 10^{-9}\times 7}{d}\\\Rightarrow d=\frac{1\times 633\times 10^{-9}\times 7}{0.35}\\\Rightarrow d=0.00001266\ m$

The slit separation is 0.00001266 m

3 0

4 years ago

A 550N object has a coefficient of .012 against a smooth surface. What

Brrunno [24]

Vertically, the object is in equilibrium, so that the net force in this direction is

∑ F (vertical) = n - mg = 0

where n is the magnitude of the normal force due to the contact between the object and surface. You're given that the object's weight is mg = 550 N, so n = 550 N as well.

Horizontally, the net force would be

∑ F (horizontal) = p - f = 0

where p is the magnitude of the applied force and f is the magnitude of (kinetic) friction opposing p. Now,

f = 0.012n = 0.012 (550 N) = 6.6 N

so that you need to apply a force of p = 6.6 N to keep the object sliding at a steady pace.

4 0

3 years ago

Two long, parallel wires are separated by a distance of 2.60 cm. The force per unit length that each wire exerts on the other is

Alex777 [14]

Answer:

10.75 A

The current is in opposite direction since it causes a repulsion force between the wires

Explanation:

Force per unit length on the wires = 4.30×10^−5 N/m

distance between wires = 2.6 cm = 0.026 m

current through one wire = 0.52 A

current on the other wire = ?

Recall that the force per unit length of two wires conducting and lying parallel and close to each other is given as

$F/l$ = $\frac{u_{0}I_{1} I_{2} }{2\pi r }$

where $F/l$ is the force per unit length on the wires

$u_{0}$ = permeability of vacuum = 4π × 10^−7 T-m/A

$I_{1}$ = current on the first wire = 0.520 A

$I_{2}$ = current on the other wire = ?

r = the distance between the two wire = 0.026 m

substituting the value into the equation, we have

4.30×10^−5 = $\frac{4\pi *10^{-7}*0.520*I_{2} }{2\pi *0.026}$ = $\frac{ 2*10^{-7}*0.520*I_{2} }{0.026}$

4.30×10^−5 = 4 x 10^-6 $I_{2}$

$I_{2}$ = (4.30×10^-5)/(4 x 10^-6) = 10.75 A

The current is in opposite direction since it causes a repulsion force between the wires.

6 0

4 years ago

the weight of an object on earth is 350 newtons. on mars the same object would weigh 134 newtons. what is the acceleration due t

Eddi Din [679]

Mass will remain constant on both planet, let mass of the object be "m".
let x be the acceleration due to gravity on the surface of mars.
Weight of object on earth = m *g , where g is acceleration due to gravity on the surface of earth
⇒350 = m * 9.8
⇒m = 350 / 9.8 .............................equation(1)
Weight of object on mars = m * x , where x is acceleration due to gravity on the surface of mars
134 = m * x .............................equation(2)
putting the value of m from equation (1) in equation(2) , we get,
x = (134 * 9.8) / 350
⇒ x = 3.572 m/s²

7 0

4 years ago

Solve this chemical equation: CH3CH2OH+__O2=CO2+__H2O

Solve this chemical equation: CH3CH2OH+O2=CO2+H2O