All categories

2 years ago

An object's mass refers to _ and an object's weight refers to _. Fill in each blank.

Physics

1 answer:

mamaluj [8]2 years ago

6 0

Answer:

Explanation:

because the more mass it has the more dense it is

You might be interested in

Two spherical drops of mercury each have a charge of 0.10 nC and a potential of 300 V at the surface. The two drops merge to for

hodyreva [135]

Answer:

$V = 228\ V$

Explanation:

given,

charge of two spherical drop = 0.1 nC

potential at the surface = 300 V

two drops merge to form a single drop

potential at the surface of new drop = ?

$V = \dfrac{kq}{r}$

$r = \dfrac{9\times 10^9\times 0.1 \times 10^{-9}}{300}$

r = 0.003 m

volume = $2 \times \dfac{4}{3}\pi r^3$

= $2 \times \dfac{4}{3}\pi \times 0.003^3$

= 2.612 × 10⁻⁷ m³

$\dfac{4}{3}\pi R^3 = 2.612\times 10^{-7}$

$R =\sqrt[3]{\dfrac{2.612 \times 10^{-7}\times 3}{4\times \pi}}$

R = 0.00396 m

$V = \dfrac{kq}{r}$

$V = \dfrac{9\times 10^9 \times 0.1 \times 10^{-9}}{0.00396}$

$V = 227.27$

$V = 228\ V$

6 0

3 years ago

A wheel is rotating at a rate of 2.0 rev every 3.0s. through what angle, in radian , does the wheel rotate in 1.0s?

igomit [66]

Answer:

$4 \pi$

Explanation:

First of all, let's convert 2.0 rev into radians:

$1.0 rev = 2\pi rad\\2.0 rev = 4 \pi rad$

This means that the angular speed of the wheel is

$\omega = 2.0 rev/s = 4 \pi rad/s$

The angle through which the wheel rotates in a time t is given by

$\theta=\omega t$

And substituting t=1.0 s, we find

$\theta=(4\pi rad/s)(1.0 s)=4 \pi rad$

7 0

3 years ago

Why does the air pressure inside the tires of a car increase when the car is driven?

Brrunno [24]

Its because particles of air inside it are moving faster and making more pressure plus there is a pressure from the street.

8 0

3 years ago

An automobile with 0.500 m radius tires travels 80,000 km before wearing them out. How many revolutions do the tires make, negle

Zinaida [17]

Answer:

n = 25,464,790.89 revolutions

The tires have made 25,464,790.89 revolutions

Explanation:

Given;

Radius of tires r = 0.5 m

Total distance travelled d = 80,000 km = 80,000,000 m

1 revolution = 2πr

Total distance d = number of revolutions n × 2πr

d = n×2πr

d = 2πnr

Making n the subject of formula;

n = d/2πr

Substituting the given values;

n = (80,000,000)/(2×π×0.5)

n = 25,464,790.89470 revolutions

n = 25,464,790.89 revolutions

The tires have made 25,464,790.89 revolutions

5 0

3 years ago

15m/s is how many Newtons

GuDViN [60]

147.09975 newton meters per second

5 0

2 years ago

An object's mass refers to _____ and an object's weight refers to _____. Fill in each blank.

An object's mass refers to _ and an object's weight refers to _. Fill in each blank.