What is the probability of choosing a day of the week that begins with T (Tuesday or Thursday)?

NEED HELP PLEASE IM BEGGING YOU !!!!! I NEED HELP WITH 6 AND 7 PLEASE

stepladder [879]

Answer:

6. is H

7. is B

Explanation:

the communitive property states that if: a+b=c, then b+a=c

if each ballon costs 2 dollars, that would b 2x or $2 (aka the 2) for 1 balloon (aka the x) and since he has a 10$ off coupon, you have to subtract 10$ so y=2x-10

5 0

3 years ago

LMNP is a rectangle. Find the value of x and the length of each diagonal. LN =7x+9 and MP=9x-9

PilotLPTM [1.2K]

Answer:

see explanation

Step-by-step explanation:

The diagonals of a rectangle are congruent, thus

MP = LN , substitute values

9x - 9 = 7x + 9 ( subtract 7x from both sides )

2x - 9 = 9 ( add 9 to both sides )

2x = 18 ( divide both sides by 2 )

x = 9

LN = 7x + 9 = (7 × 9) + 9 = 63 + 9 = 72

MP = 9x - 9 = (9 × 9) - 9 = 81 - 9 = 72

7 0

3 years ago

Bill is planning a trip from detroit to london with a stopover in new york. his flight to new york is 2 hours long. if his stopo

Anon25 [30]

He will land in london at 1am

4 0

3 years ago

Given the vectors A⃗ and B⃗ shown in the figure ((Figure 1) ), determine the magnitude of B⃗ −A⃗. A is 28 degrees above the posi

Vlad [161]

This problem is represented in the Figure below. So, we can find the components of each vector as follows:

$\bullet \ cos(28^{\circ})=\frac{Adjacent}{Hypotenuse}=\frac{A_{x}}{44} \\ \\ \therefore A_{x}=44cos(28^{\circ})=38.85m \\ \\ \\ \bullet \ sin(28^{\circ})=\frac{Opposite}{Hypotenuse}=\frac{A_{y}}{44} \\ \\ \therefore A_{y}=44sin(28^{\circ})=20.65m$

$\bullet \ cos(56^{\circ})=\frac{Adjacent}{Hypotenuse}=\frac{-B_{x}}{26.5} \\ \\ \therefore B_{x}=-26.5cos(56^{\circ})=-14.81m \\ \\ \\ \bullet \ sin(56^{\circ})=\frac{Opposite}{Hypotenuse}=\frac{B_{y}}{26.5} \\ \\ \therefore B_{y}=26.5sin(56^{\circ})=21.97m$

Therefore:

$\vec{A}=(38.85, 20.65)m \\ \\ \vec{B}=(-14.81, 21.97)m$

So:

$\vec{B}-\vec{A}=(-14.81, 21.97)-(38.85, 20.65)=(-53.66,1.32)$

Finally, the magnitude is:

$\boxed{\left| \vec{B}-\vec{A}\right|=\sqrt{(-53.66)^2+(1.32)^2}=53.67m}$

7 0

3 years ago

Read 2 more answers

A county government says that a safe level of chlorine in a hot tub is within 1.75 ppm of 3.25 ppm.

Schach [20]

Answer:

Part A : |x-2.5| ≤ 0.75 , x ∈ [1.75,3.5]

Part B : yes, the lifeguard should add more chlorine.

Step-by-step explanation:

Part A:

Let C is the variation of the level of chlorine in a hot tub.

Level of chlorine in a hot tub is within 1.75 ppm of 3.25 ppm.

To find absolute value inequality, need to find the standard level of chlorine 1.75 + C or 3.25 - C

1.75 + C = 3.25 - C

2C = 5

C = 2.5

So, the standard level would be 2.5 ppm,

If x represents the present level of chlorine,

Then it would be lie within 1.75 ppm of 3.25 ppm.

1.75 ≤ x ≤ 3.25

Subtract 2.5 from all sides

1.75 - 2.5 ≤ x -2.5 ≤ 3.25 - 2.5

-0.75 ≤ (x-2.5) ≤ 0.75

which is equivalent to the following absolute value inequality.

|x-2.5| ≤ 0.75

And the solve of the inequality : x ∈ [1.75,3.5]

Part B: If x = 1.0 ppm,

∴ |1.0-2.5| = 1.5 which is not less than equal to 0.75.

Another explanation:

the minimum safe level of chlorine in a hot tub is 1.75 ppm

Since 1 < 1.75

Therefore, lifeguard should add more chlorine.

8 0

4 years ago