Oxidation number of fe in the compound...,
Let the oxidation number of (Fe) be x
The oxidation number of oxygen(o) is (-2)
; 3x + 4(-2) = 0...where zero is the total charge on the compound(fe3o4)
; 3x = 8...then divide both sides by 3
Oxidation number of fe is( 2.67 )
is an outer shell electron that is associated with an atom
Given data:
Distance travelled (d)= 200.0 m
Time taken (t) = 21.7 s
To determine:
The average speed in km/hr
Calculation:
Convert distance from m to km
1000 m = 1 km
200.0 m = 1 km * 200.0 m/1000 m = 0.2 km
Convert time from sec to hours
3600 sec = 1 hour
21.7 sec = 1 hour * 21.7 sec/3600 sec = 6.027 *10^-3 hrs
Speed is defined as the amount of distance travelled per unit time
Speed = distance/time = 0.2 km/6.027*10^-3 hr
= 33.18 km/hr (or 33.2 km/hr)
Answer: It's 2:2
Explanation: you can look at the coefficient stands in front of the chemical
For example if they ask the ratio of oxygen to sulfur trioxide, it would be 3:2 and vice versa vv..
I believe it's fractional perspective
