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3 years ago

Combustion analysis of a hydrocarbon produced 33.01 g co2 and 13.52 g h2o. calculate the empirical formula of the hydrocarbon.

1 answer:

6 0

Answer is: the empirical formula of the hydrocarbon is CH₂.
Chemical reaction: CₓHₐ + O₂ → xC + a/2H₂O.
m(CO₂) = 33.01 g.
n(CO₂) = m(CO₂) ÷ M(CO₂).
n(CO₂) = 33.01 g ÷ 44.01 g/mol.
n(CO₂) = n(C) = 0.75 mol.
m(H₂O) = 13.52 g.
n(H₂O) = 13.52 g ÷ 18 g/mol.
n(H₂O) = 0.75 mol.
n(H) = 2 · n(H₂O) = 1.5 mol.
n(C) : n(H) = 0.75 mol : 1.5 mol /0.75 mol.
n(C) : n(H) = 1 : 2.

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According to the iupac convention, alkyl substituents on a hydrocarbon chain should be listed in which order?

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1 year ago

A 5.00 gram sample of an oxide of lead PbxOy contains 4.33g of lead. Determine the simplest formula for the compound.

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PbO2

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3 years ago

2LiClO+KHSO - Li2SO4 + Cl2 + KOOH

agasfer [191]

Answer:

2.5 moles of KOOH are produced.

Explanation:

1)Given data:

Number of moles of KOOH produced = ?

Number of moles of LiClO = 5 mol

Solution:

Chemical equation:

2LiClO + KHSO₄ → Li₂SO₄ + Cl₂ + KOOH

now we will compare the moles of KOOH and LiClO.

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2 : 1

5 : 1/2×5 = 2.5

2.5 moles of KOOH are produced.

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3 years ago

Which one is it? Please help

DedPeter [7]

Answer:

D: 60 grams.

Explanation:

If you look at the x-axis and where it says 50 degrees Celsius, you can see that it takes 20 grams of solute to be saturated at 100 GRAMS of solvent. However, the question is asking for the amount of solute to saturate a 300 GRAM solution.

This means you will have to multiply the amount of solute needed at 100 grams by 3 to get you to the amount needed for 300 grams.

20 times 3 will get you to your answer, 60 grams.

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