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iren2701 [21]
2 years ago
10

In order for a process to be spontaneous, Multiple Choice the entropy of the surroundings must increase. the entropy of the surr

oundings must decrease. the entropy of the system must increase. the entropy change of the surroundings plus the entropy change of the system must be positive. the entropy of the universe must decrease.
Chemistry
1 answer:
Crazy boy [7]2 years ago
8 0

Answer:

The correct answer is entropy change of the surrounding plus the entropy change of the system must be positive.

Explanation:

The term entropy is a state function.Entropy can be defined as the disorder or randomness of the molecules in a system.

 A spontaneous reaction is a type of reaction which deals with the release of free energy.The change of free energy in case of spontaneous reaction is always negative.

 According to the second law of thermodynamics a spontaneous reaction will occur in a system if the total entropy of both  system and surrounding increases during the reaction.

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Explanation:

7 0
2 years ago
any time an energy conversion takes place, some of the original energy is converted to which one of the following?
Charra [1.4K]

Answer:

Thermal energy.

Explanation:

Anytime energy transfers between 2 places or things some of it is 'wasted' as thermal energy (heat). This could be by friction or a change in temperature from a reaction. We say it is wasted because this heat energy serves no purpose.

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2 years ago
Neon doesn't take part in chemical reaction why give reason​
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Read 2 more answers
Sulfur undergoes combustion to yield sulfur trioxide by the following reaction equation:
12345 [234]

Answer:

Therefore, the amount of heat produced by the reaction of 42.8 g S = <u>(-5.2965 × 10²) kJ = (-5.2965 × 10⁵) J</u>

Explanation:

Given reaction: 2S + 3O₂ → 2 SO₃

Given: The enthalpy of reaction: ΔH = - 792 kJ

Given mass of S: w₂ = 42.8 g, Molar mass of S: m = 32 g/mol

In the given reaction, the number of moles of S reacting: n = 2

As, Number of moles: n = \frac{mass\: (w_{1})}{molar\: mass\: (m)}

∴  mass of S in 2 moles of S: w_{1} = n \times m = 2\: mol \times 32\: g/mol = 64\: g

<em>Given reaction</em>: 2S + 3O₂ → 2 SO₃

<em>In this reaction, the limiting reagent is S</em>

⇒ 2 moles S produces (- 792 kJ) heat.

or, 64 g of S produces (- 792 kJ) heat.

∴ 42.8 g of S produces (x) amount of heat

⇒ <u><em>The amount of heat produced by 42.8 g S:</em></u>

x = \frac{(- 792\: kJ) \times 42.8\: g}{64\: g} = (-529.65)\: kJ

\Rightarrow x = (-5.2965 \times 10^{2})\: kJ = (-5.2965 \times 10^{5})\: J

(\because 1 kJ = 10^{3} J)

<u>Therefore, the amount of heat produced by the reaction of 42.8 g S = (-5.2965 × 10²) kJ = (-5.2965 × 10⁵) J</u>

8 0
3 years ago
What are the answers please help
LenaWriter [7]
Thank you for the free 15 points .
4 0
2 years ago
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