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dalvyx [7]
3 years ago
8

What’s the lowest point of a wave called

Chemistry
2 answers:
Anni [7]3 years ago
8 0

ANSWER:

the lowest part of a wave is called the trough

~batmans wife dun dun dun...aka ~serenitybella

ioda3 years ago
6 0

it is called the trough.

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Please can you help me from 1 to 6
jeyben [28]

Answer:

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Explanation:

help you? you mean do it for you? nah man you can just use the calculator ;)

4 0
3 years ago
Select the correct answer. which tool is used to measure an object’s mass? a. graduated cylinder b. meter stick c. digital therm
zavuch27 [327]

The tool or instrument which is used to measure an object’s mass is electronic balance

Mass is a fundamental quantity

<h3>What is fundamental quantities?</h3>

Fundamental quantities can be defined as those physical quantities which forms the basic unit of measurement. They are the quantities upon which other quantities and units are derived from.

Mass is measured in kilograms (kg)

Other examples of fundamental quantities apart from mass are as follows:

  • Length
  • Time
  • Amount of substances
  • Luminous intensity
  • Temperature
  • Magnetic flux

So therefore, the tool or instrument which is used to measure an object’s mass is electronic balance

Learn more about fundamental/physical quantities:

brainly.com/question/23036403

#SPJ1

6 0
2 years ago
When forming ions, metals typically do which of the following?
MrRissso [65]
Metals usually melt when forming iron
5 0
2 years ago
Read 2 more answers
What is the percent yield if 107.50 g NH3 reacts with excess O2 according to the
Maksim231197 [3]

Answer:

81.59%

Explanation:

  • 4NH₃ + 5O₂ → 4NO + 6H₂O

First we <u>convert 107.50 g of NH₃ into moles</u>, using its <em>molar mass</em>:

  • 107.50 g NH₃ ÷ 17 g/mol = 6.32 mol NH₃

Now we <u>calculate how many moles of NO would have been formed by the complete reaction of 6.32 moles of NH₃</u>:

  • 6.32 mol NH₃ * \frac{4molNO}{4molNH_3} = 6.32 mol NO

Then we <u>convert 6.32 moles of NO to grams</u>, using its <em>molar mass</em>:

  • 6.32 mol NO * 30 g/mol = 189.60 g NO

Finally we <u>calculate the percent yield</u>:

  • 154.70 g / 189.60 g * 100% = 81.59%

8 0
3 years ago
The 3 components of air
jok3333 [9.3K]

Nitrogen (around 78%), Oxygen (around 21%), and Argon (around 1%).

Hope this helps :)

8 0
3 years ago
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