Evet canım çok teşekkür ederim canım benim için çok teşekkür ederimmm
Answer:
It will be 16/8 I hope you are happy
Answer:
basicaly your asking to be fulled so {{64
Step-by-step explanation:
Answer:
The best choice would be hiring a random employee from company A
Step-by-step explanation:
<em>Supposing that the performance rating of employees follow approximately a normal distribution on both companies</em>, we are interested in finding what percentage of employees of each company have a performance rating greater than 5.5 (which is the mean of the scale), when we measure them in terms of z-scores.
In order to do that we standardize the scores of both companies with respect to the mean 5.5 of ratings
The z-value corresponding to company A is

where
= mean of company A
= 5.5 (average of rating between 1 and 10)
s = standard deviation of company A

We do the same for company C

This means that 27.49% of employees of company C have a performance rating > 5.5, whereas 71.42% of employees of company B have a performance rating > 5.5.
So, the best choice would be hiring a random employee from company A
The answer would be 4 bc 5 minus 1 is 4. x = 4. y = 4.