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3 years ago

Solve: 2x - 3 = 2x - 5

Mathematics

1 answer:

trapecia [35]3 years ago

5 0

0=2 so no solution I hope this helps

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Math Question:<br> Pls help I will do anything

kow [346]

Answer:

The probability of spinning red is $\frac{1}{3}$ , the probability of spinning a 1 is $\frac{1}{6}$ , the probability of spinning an odd number is $\frac{1}{2}$ , and the probability of spinning a 9 is 0.

Step-by-step explanation:

Since there are a total of 6 possible outcomes, you can use this in the following questions. There are 2 red tiles, so the probability of spinning red is $\frac{2}{6}$ or $\frac{1}{3}$ . Since there are only one 1 tile, the probability of spinning a 1 is $\frac{1}{6}$ . Since there are three odd numbers, the probability of spinning an odd number is $\frac{1}{2}$ . Since there are no 9 in the spinner, the probability of spinning a 9 is 0 or never.

5 0

3 years ago

I need help with this yes or no picking?

Ivenika [448]

Use photomath. Do not click on the link the other person which is actually a bot put.

6 0

3 years ago

HELPPPP ASAPPP PLEASSSSEE

kolezko [41]

Let dimes = d and quarters =q

D + q = 50

D= 50-q

0.10d + 0.25Q = 7.70

Replace d with 50-q:

0.10(50-q) + 0.25q = 7.70

Simplify:

5 -0.10q + 0.25q = 7.70

5 + 0.15q = 7.70

Subtract 5 from both sides:

0.15q = 2.70

Divide both sides by 0.15:

Q = 2.70 / 0.15

Q = 18

D = 50-18 = 32

There are 32 dimes and 18 quarters

5 0

3 years ago

Read 2 more answers

A charger costs $6. How much would you need to pay after 10% sales tax has been applied?

Vanyuwa [196]

Depends on the state but lmk

8 0

3 years ago

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A television network is deciding whether or not to give its newest television show a spot during prime viewing time at night. If

Alinara [238K]

Answer:

Test statistic z= 1.708

Step-by-step explanation:

given that a television network is deciding whether or not to give its newest television show a spot during prime viewing time at night. If this is to happen, it will have to move one of its most viewed shows to another slot.

Sample size n = 827

Sample proportion p = $\frac{438}{827} \\=0.5297$

$H_0: p =0.5\\H_a: p >0.5$

(right tailed test)

This is because they would be interested if more than half viewers are ready for the change

Test statistic = Z = p difference/std error

p difference = 0.0297

Std error = $\sqrt{\frac{pq}{n} } \\=\sqrt{\frac{0.5*0.5}{827} } \\=0.0174$

Z =1.708

p valu e= 0.9562

Since p >0.05 we fail to reject H0

Test statistic z= 1.708

8 0

3 years ago

Solve: 2x - 3 = 2x - 5​

Solve: 2x - 3 = 2x - 5