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3 years ago

Please help Assssaaaappp!!! almost due and im having trouble.

Mathematics

1 answer:

USPshnik [31]3 years ago

3 0

A. Nancy has the greatest spread because her longest training time was 105 and her shortest being 82, making the spread 23, and Peter’s spread is only... Longest: 112 Shortest: 92 making it 20!
b. Nancy. Middle %50 would be Peter’s 110-92 making the spread 18, and Nancy’s spread is 93-90 making the spread making it 12
c. The spreads tell us they are very close to each other, and just Peter has more time but a less spread than Nancy.

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5x-9=-59. What does x equal?

Aleonysh [2.5K]

X = -10

5x - 9 = -59
+9 + 9
5x = -50
/5 /5
x = -10

6 0

3 years ago

Read 2 more answers

Work out the size of angle x

Alik [6]

Answer:

∠x = 117°

Step-by-step explanation:

supplement of ∠101° = 79°

all triangle interior angles add up to 180°

180° - 79° - 38° = 63°

the supplementary angle to 63° is 117°

6 0

3 years ago

Find the extreme values of the function f(x, y) = 4x2 + 6y2 on the circle x2 + y2 = 1.

julia-pushkina [17]

Answer with Step-by-step explanation:

We are given that

$f(x,y)=4x^2+6y^2$

Let g(x,y)= $x^2+y^2=1$

We have to find the extreme values of the given function

$\nabla f(x,y)$

$\nabla g(x,y)=$

Using Lagrange multipliers

$\nabla f(x,y)=\lambda \nabla g(x,y)$

$f_x=\lambda g_x$

$8x=\lambda 2x$

Possible value x=0 or $\lambda=4$

If x=0 then substitute the value in g(x,y)

Then, we get $y=\pm 1$

$f_y=\lambda g_y$

$12y=\lambda 2y$

If $\lambda=4$ and substitute in the equation

Then , we get possible value of y=0

When y=0 substitute in g(x,y) then we get

$x=\pm 1$

Hence, function has possible extreme values at points (0,1),(0,-1), (1,0) and (-1,0).

$f(0,1)=6$

$f(0,-1)=6$

$f(1,0)=4$

$f(-1,0)=4$

Therefore, the maximum value of f on the circle $x^2+y^2=1$ is $f(0,\pm1)=6$ and minimum value of $f(\pm1,0)=4$

7 0

3 years ago

Membership in an elite organization requires a test score in the upper 30% range. If the mean is equal to 115 and the standard d

Olenka [21]

Answer:

Lowest acceptable score = 121.3

Step-by-step explanation:

Mean test score (μ) = 115

Standard deviation (σ) = 12

The z-score for any given test score 'X' is defined as:

$z=\frac{X-\mu}{\sigma}$

In this situation, the organization is looking for people who scored in the upper 30% range, that is, people at or above the 70-th percentile of the normally distributed scores. At the 70-th percentile, the corresponding z-score is 0.525 (obtained from a z-score table). The minimum score, X, that would enable a candidate to apply for membership is:

$0.525=\frac{X-115}{12}\\X=121.3$

4 0

4 years ago

√m/3=4<br> My teacher didn't explain how to solve these to well can someone explain?

Andrews [41]

√m/3 = 4

To remove the radical sign, square both sides.

(√m/3)² = 4²
m/3 = 16

To remove the denominator of 3, multiply both sides by 3.
3 (m/3) = 3(16)
m = 48

To check: Substitute m by its value.
√m/3 = 4
√48/3 = 4
√16 = 4
4 = 4

4 0

3 years ago