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3 years ago

Find the quotient. 6^8/6^6

2 answers:

8 0

The answer would be 1^2.

To find this, first you divide 6 (numerator) by 6 (denominator) to get 1. Then you subratct the power of 6, from the power of 8, to get 2. Thus getting a final answer of 1^2.

I hope this helps!

qaws [65]3 years ago

7 0

6^2
Because 8 - 6 = 2

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Kathryn rented the bike for about 1.7 hours.

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3 years ago

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A 100 gallon tank initially contains 100 gallons of sugar water at a concentration of 0.25 pounds of sugar per gallon suppose th

Vsevolod [243]

At the start, the tank contains

(0.25 lb/gal) * (100 gal) = 25 lb

of sugar. Let $S(t)$ be the amount of sugar in the tank at time $t$ . Then $S(0)=25$ .

Sugar is added to the tank at a rate of P lb/min, and removed at a rate of

$\left(1\frac{\rm gal}{\rm min}\right)\left(\dfrac{S(t)}{100}\dfrac{\rm lb}{\rm gal}\right)=\dfrac{S(t)}{100}\dfrac{\rm lb}{\rm min}$

and so the amount of sugar in the tank changes at a net rate according to the separable differential equation,

$\dfrac{\mathrm dS}{\mathrm dt}=P-\dfrac S{100}$

Separate variables, integrate, and solve for S.

$\dfrac{\mathrm dS}{P-\frac S{100}}=\mathrm dt$

$\displaystyle\int\dfrac{\mathrm dS}{P-\frac S{100}}=\int\mathrm dt$

$-100\ln\left|P-\dfrac S{100}\right|=t+C$

$\ln\left|P-\dfrac S{100}\right|=-100t-100C=C-100t$

$P-\dfrac S{100}=e^{C-100t}=e^Ce^{-100t}=Ce^{-100t}$

$\dfrac S{100}=P-Ce^{-100t}$

$S(t)=100P-100Ce^{-100t}=100P-Ce^{-100t}$

Use the initial value to solve for C :

$S(0)=25\implies 25=100P-C\implies C=100P-25$

$\implies S(t)=100P-(100P-25)e^{-100t}$

The solution is being drained at a constant rate of 1 gal/min; there will be 5 gal of solution remaining after time

$1000\,\mathrm{gal}+\left(-1\dfrac{\rm gal}{\rm min}\right)t=5\,\mathrm{gal}\implies t=995\,\mathrm{min}$

has passed. At this time, we want the tank to contain

(0.5 lb/gal) * (5 gal) = 2.5 lb

of sugar, so we pick P such that

$S(995)=100P-(100P-25)e^{-99,500}=2.5\implies\boxed{P\approx0.025}$

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2 years ago

16 - (1 - 5x) - 4x-29

Lera25 [3.4K]

-14 + x

Is the correct answer

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3 years ago

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Aaron invested $740 in an account paying an interest rate of 5%

vlada-n [284]

The amount of money Justin would have in his account than Aaron, to the nearest dollar is $0

What is the future value formula for continuous compounding cash flow?

The future value, which is used to determine the worth of this investment of $740 made now in 18 years is as shown below:

FV=PV*e^(rt)

FV=the worth of the investment in 18 years=unknown

PV=the amount invested today=$740

e=mathematical exponential value=2.7182818

r=rate of interest which compounded continuously=5%

t=time of investment in years=18

FV=$740*2.7182818^(5%*18)

FV=$740*2.7182818^(0.90)

FV=$740*2.459603087981220

FV=$1,820.11

Justin:

FV=PV*(1+r/m)^(n*m)

PV=$740

r=5%

m=number of times in a year that interest is compounded=365

m=number of years=18

FV=$740*(1+5%/365)^(18*365)

FV=$1,819.99

difference=$1,820.11-$1,819.99

difference=$0.12($0 to the nearest dollar)

Find out more about continuous compounding on:brainly.com/question/23136156

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1 year ago

In a certain grocery store, strawberries cost $6.40 per pound ( 6.40 dollars/lb ). What is the cost per ounce?

Nastasia [14]

Solution:

we are given that

In a certain grocery store, strawberries cost $6.40 per pound ( 6.40 dollars/lb ).

we have been asked to find the cost per ounce?

As we know that

16 oz=1 lb

so we will divide by 16 to get the cost per ounce.

strawberries cost $6.40 per pound so for 1 oz it will cost $=\frac{6.40}{16}= 0.4$ $

Hence cost per ounce is 0.40 $

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