1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
iVinArrow [24]
3 years ago
6

Help please if you know this I will appreciate it thank you

Physics
1 answer:
aev [14]3 years ago
3 0
The independent variable is the one thing that changes in the experiment, the dependent is what you are measuring, and controlled is all the things you keep the same and never change. So for the first one I=different tire trends (change it each time), D=breaking distance (what you are measuring) and C=use the same car, same brand of tires, same brand of brakes, run cars on same surface etc..
Hope this helps!
You might be interested in
What is the kinetic energy of a 478 kg object that is moving with a speed of 15 m/s
Tpy6a [65]
The kinetic energy would be 53,775J:)
7 0
3 years ago
A wave with a frequency of 325 Hz. is travelling at a speed of 125 m/s. What is the wavelength of this wave?
ollegr [7]

Answer:

0.385 meters

Explanation:

Just remember this very simple equation:

velocity=(wavelength)*(frequency)

I always remember it as "Velma is Waving Frantically"

So, 125=(wavelength)*(325)

Therefore, wavelength=0.385 meters!

Hope this helped!

4 0
3 years ago
A solenoid 50-cm long with a radius of 5.0 cm has 800 turns. You find that it carries a current of 10 A. The magnetic flux throu
ioda

Answer:

126 mWb

Explanation:

Given that:

length (L) = 50 cm = 0.5 m, radius (r) = 5 cm = 0.05 m, current (I) = 10 A, number of turns (N) = 800 turns.

We assume that the magnetic field in the solenoid is constant.

The magnetic flux is given as:

\phi_m=NBAcos(\theta)\\Where\ B\ is\ the\ magnetic\ field\ density,A\ is \ the\ area.\\But\ B =\mu_onI.\ n \ is\ the\ number\ of\ turns\ per\ unit \ length=N/L\\Therefore,B=\frac{\mu_oNI}{L} \\substituting\ the\ value\ of\ B\ in\ the\ equation: \\\phi_m=\frac{NAcos(\theta)*\mu_oNI}{L} .\ But \ \theta=0,cos(\theta)=1\ and\ A=\pi r^2\\ \phi_m=\frac{N^2\pi r^2\mu_oI}{L} \\Substituting\ values:\\\phi_m=\frac{800^2*(\pi*0.05^2)*(4\pi*10^{-7})*10}{0.5}=0.126\ Wb=126\ mWb

8 0
3 years ago
In reaching her destination, a backpacker walks with an average velocity of 1.41 m/s, due west. This average velocity results, b
V125BC [204]
The total average velocity v=+1.41 m/s (I assume west as positive direction) is given by the total displacement, S, divided by the total time taken, t:
v= \frac{S}{t}= \frac{S_1+S_2}{t_1+t_2}
where:
-The total displacement S is the algebraic sum of the displacement in the first part of the motion (S_1=6.30 km=6300 m, due west) and of the displacement in the second part of the motion (S_2, due east).
-The total time taken t is the time taken for the first part of the motion, t_1, and the time taken for the second part of the motion, t_2. t_1 can be found by using the average velocity and the displacement of the first part:
t_1= \frac{S_1}{v_1}= \frac{6300 m}{2.49 m/s}=2530 s

t_2, instead, can be written as \frac{S_2}{v_2}, where v_2=-0.630 m/s is the average velocity of the second part of the motion (with a negative sign, since it is due east). 

Therefore, we can rewrite the initial equation as:
v=1.41 = \frac{6300+S_2}{2530- \frac{S_2}{0.630} }
And by solving it, we find the displacement in the second part of the motion (i.e. how far did the backpacker move east):
S_2=-844 m=-0.844 km

4 0
3 years ago
An airplane pilot sets a compass course due west and maintains a speed of 220 km/h. after flying for a half hour she finds herse
timurjin [86]

The net speed due west is = distance traveled in west / time taken = 120/0.5 = 240 km/h.  

so airspeed due west is  = net speed - speed of plane = 240-220= 20 km/h.  

airspeed due south is = distance traveled in west / time taken= 20/0.5= 40 km/h.  

the magnitude of the wind velocity = √[(airspeed due south )² + (airspeed due west)²] = √ ( 40^2 + 20^2 ) = 44.72 km/h

the angle of airspeed south of west is tan⁻¹ ( airspeed due south / airspeed due west )= tan⁻¹(40/20)=63.43 degrees.  

if wind velocity is 40 km/h due south, her velocity should have 20 km/h component in north.

so component west = sqrt ( 220^2 - 40^2 ) = 216.33 km/h.  

the angle north of west is arctan( 40/216.33 ) = 10.47 degrees.

5 0
3 years ago
Read 2 more answers
Other questions:
  • Speed training increases one's maximum velocity.<br> a. True<br> b. False
    10·2 answers
  • The automobile has a weight of 2700 lb and is traveling forward at 4 ft&gt;s when it crashes into the wall. If the impact occurs
    10·1 answer
  • An example of a high explosive is what?
    14·2 answers
  • What was the greatest discovery by galileo during his inclined-plane experiments?
    7·1 answer
  • For each of the
    14·1 answer
  • Apply the general results obtained in the full analysis of motion under the influence of a constant force in Section 2.5 to answ
    9·1 answer
  • Write how gravity and the mass of the pack affected the motion of the pack when it was thrown at different forces.
    6·1 answer
  • 24. A car is travelling along an expressway at 90 km/h. The driver spots a stalled car and some traffic congestion on the road a
    8·1 answer
  • Starting from rest, a racing car has a displacement of 201 m, S, in the first 5.0 s of uniform acceleration. What is the car's a
    11·1 answer
  • HELP
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!