Question 2: Answer is (B), Soil Conservation Act (1936)
Hope that helps!!!
Answer:
The equilibrium constant Ksp of the generic salt AB2 = 6.4777 *10^-8 M
Explanation:
Step 1: The balanced equation
AB2 ⇒ A2+ + 2B-
Step 2: Given data
Concentration of A2+ = 0.00253 M
Concentration of B- = 0.00506 M
Step 3: Calculate the equilibrium constant
Equilibrium constant Ksp of [AB2] = [A2+][B-]²
Ksp = 0.00253 * 0.00506² = 6.4777 *10^-8 M
The equilibrium constant Ksp of the generic salt AB2 = 6.4777 *10^-8 M
Answer:
(Hope this helps can I pls have brainlist (crown)☺️)
Explanation:
Dalton turned Democritus' views on atoms into a scientific theory by employing experimental methods. Atoms can join or detach during chemical processes, but they never transform into a different atom.
Dalton was an excellent polymath, a natural philosopher, and a real scientist. His thorough investigations prompted him to suggest an early atomic theory for which exceptions would be difficult to uncover today:
Dalton offered the following:
Atoms are microscopic particles that make up elements. Atoms of the same element have the same size and mass; however, atoms of other elements have varying sizes and masses when compared to atoms of other elements. Subdivision, creation, and destruction of atoms are all impossible.
All of these ideas were developed after a great deal of testing. Other researchers may replicate his work, and new findings could be included into this atomic idea.
Democritus, on the other hand, was a 5th-century BC Greek philosopher. He conducted no experimental work as far as we know, and none of his publications have survived. He postulated that matter was made up of a single indivisible element known as an atom; the word atom originates from the Greek word oos, which meaning "uncuttable" or "indivisible." So the name atom might be a homage to Democritus.
Answer:
-3
Explanation:
The oxidation state or oxidation number of an atom is the total number of electrons that an atom either gains or loses in order to form a chemical bond with another atom.
The complex anion here is [Cr(CN)6]3-.
Now, as the oxidation state of CN or cyanide ligand is -1, and if we suppose the oxidation state of Cr to be 'x', then; x - 6 = -3 (overall charge on the anion),
so x= +3. Hence the oxidation state of Chromium in this complex hexacyanochromium (III) anion comes out to be -3.
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Answer:
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Explanation:
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