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Katen [24]
3 years ago
6

How many grams of the excess reagent are left over if 37.8g of Cl2 react with 39.4 g of NaF?

Chemistry
1 answer:
tia_tia [17]3 years ago
5 0

Answer:

Explanation:

Panther how many million vacation bigger than I think a 20 kg in the

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7. if you kick a tennis ball with 50 N of force and then kick a soccer ball with 50 N of force,
BabaBlast [244]

Answer:

It depends of how heavy the object is so i would say the tennis ball would go the farthest. And the amount of air it has!

Explanation:

5 0
3 years ago
Help Me plz I'm so tired
zvonat [6]
The answer is D :) have a nice day!
3 0
3 years ago
Read 2 more answers
For the reaction, 2A + B → 3C, rate of disappearance of A is 0.3 M/s in a certain time interval.What is the average rate of appe
andrezito [222]

Answer:

E) rate of appearance of C = 0.45 M/s

rate of the reaction = 0.15 M/s

Explanation:

2A + B → 3C

Writing rate law for the reaction:

<u>Rate of reaction</u> = -\frac{1}{2}\frac{d[A]}{dt} = -\frac{d[B]}{dt} = \frac{1}{3}\frac{d[C]}{dt} → equation 1

Given that the rate of disappearance of A is 0.3 M/s

⇒ - \frac{d[A]}{dt} = 0.3 M/s

⇒Rate of reaction = - \frac{1}{2}\frac{d[A]}{dt} = \frac{1}{2}×0.3 M/s

⇒<u>Rate of reaction = 0.15 M/s</u>

From equation 1, \frac{d[C]}{dt} = - \frac{3}{2}\frac{d[A]}{dt} = \frac{3}{2}×0.3 M/s

⇒\frac{d[C]}{dt} = 0.45 M/s

or <u>the rate of appearance of C = 0.45 M/s</u>

7 0
3 years ago
1. Illustrate and describe the sequence in which ten electrons occupy the five
gladu [14]
10 electrons will occupy the five orbitals in the atoms d sub shell like this. Each electron fills one by one in each orbital. So first 1 electron will fill the first orbital, then the second will move on to the next and so on. So for example…if there were 7 electrons, the first two sub shells would be filled, and the other three would have one electron each

8 0
2 years ago
How many kilograms of dry air are in a room that measures 15.0 ft by 18.0 ft by 8.00 ft? Use the density of air of 1.168 g/L. Th
Nady [450]

Answer:

0.0481 kg.

Explanation:

First, we need to find the volume of the room.

15 x 18 x 8 = 1350

The volume of the room is 1350 ft³

Now, we convert feet to centimeters

1350 x 30.48 = 41,148

The volume is 41,148 cm³

1 cm³ = 1 mL

So we can say that the volume of the room is also 41,148 mL

Then, we convert milliliters to liters

41,148 ÷ 1,000 = 41.148

There are 41.148 liters of air in the room

We multiply the air's density with volume in liters

41.148 x 1.168 = 48.060864

There are 48.060864 grams of air in the room

Finally, convert grams to kilograms

48.060864 ÷ 1,000 = 0.048060864

0.048060864 kilograms of air are in the room.

4 0
3 years ago
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