How many grams of the excess reagent are left over if 37.8g of Cl2 react with 39.4 g of NaF?
1 answer:
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Answer:
Explanation:
The average atomic mass is the sum of the product of the given masses and their abundances. We have to complete two steps for each isotope, then add all the products together.
<u>Fe-54</u>
Convert the percent abundance to a decimal by dividing by 100.
- 5.845/100= 0.05845
Multiply the abundance as a decimal by the mass number. This is the number after the element in the isotope symbol (54 amu).
- 0.005845 * 54=3.1563 amu
<u>Fe-56</u>
Convert the percent to a decimal.
- 91.754/100=0.91754
Multiply the decimal by the mass number (56 amu).
- 0.91754 * 56= 51.38224 amu
<u>Fe-58</u>
Convert the percent to a decimal.
- 2.119/100=0.02119
Multiply by the mass number (58 amu).
- 0.02119 * 58 = 1.22902 amu
<u>Average Atomic Mass</u>
Add all the products together to find the average atomic mass.
- 3.1563 amu + 51.38224 amu + 1.22902 amu =55.76756 amu
The average atomic mass given the percent abundance is <u>55.7656 atomic mass units.</u>
