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-Dominant- [34]
3 years ago
13

Look at the diagram of the atom. What will it change to during beta decay? A)An atom with 3 protons, 4 neutrons, and 3 electrons

B)An atom with 3 protons, 4 neutrons, and 4 electrons C)An atom with 4 protons, 3 neutrons, and 4 electrons D)An atom with 4 protons, 3 neutrons, and 3 electrons

Chemistry
1 answer:
GREYUIT [131]3 years ago
5 0
D) An atom with 4 protons, 3 neutrons, and 3 electrons
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Ganezh [65]
Li2O + H2O → 2LiOH
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3rd blank write 2
3 0
3 years ago
Helium is the lightest noble gas and the second most abundant element (after hydrogen) in the universe. The mass of a helium−4 a
dmitriy555 [2]

<u>Answer:</u> The fraction of atom's mass contributed by nucleus is 0.99

<u>Explanation:</u>

Nucleons are defined as the sub-atomic particles which are present in the nucleus of an atom. Nucleons are protons and neutrons.

The isotopic symbol of Helium-4 atom is _2^4\textrm{He}

Number of electrons = 2

Number of protons = 2

Number of neutrons = 4 - 2 = 2

We are given:

Mass of He-4 atom = 6.64648\times 10^{-24}g

Mass of 1 electron = 9.10939\times 10^{-28}g

Calculating the mass contributed by the nucleus = m_{He}-2(m_e)

Mass of the nucleus of He-4 atom = 6.64648\times 10^{-24}-(2\times (9.10939\times 10^{-28}))=(6.64648-0.0018219)\times 10^{-24}=6.64466\times 10^{-24}

To calculate the fraction of atom's mass contributed by the nucleus, we use the equation:

\text{Fraction of atom's mass contributed by nucleus}=\frac{\text{Mass of nucleus}}{\text{Mass of atom}}

Putting values in above equation, we get:

\text{Fraction of atom's mass contributed by nucleus}=\frac{6.64466\times 10^{-24}g}{6.64648\times 10^{-24}g}=0.99

Hence, the fraction of atom's mass contributed by nucleus is 0.99

8 0
2 years ago
What is the mass of a sample of pure gold containing 3.00 x 1024 gold atoms?
miss Akunina [59]

Answer: The mass is 980.6g of Gold.

Explanation:

We begin by looking for the number of moles equivalent to 3.0 x 10^24 gold atoms.

Using the Avogadro's number,

6.02 x 10^23 atoms of gold make up 1 mole of gold.

3.0 x 10^24 atoms would make up: 1 / 6.02 x 10^23 x 3.0 x 10^24 = 4.98moles.

Now that we know the number of moles, we can then look for the mass using the formular:

Moles = mass/ molar mass

4.98 = mass / 196.9 (atomic mass of gold)

Making "mass" the subject of formula : mass = 4.98 x 196.9= 980.6g

8 0
3 years ago
If a man has a mass of 83 kilograms on Earth, what will the force of gravity on his body be on the moon? A. 135.6 N B. 318.5 N C
diamong [38]
First, we need to know what's the gravity value in the moon. it is 1.622 m/ s2

to find the force, let's recall this formula----> Force= mass x gravity

force= 83 kg x 1.622= 134.6

A is the closest choice.
4 0
3 years ago
Read 2 more answers
Calculate the amount of water required to prepare 500g of 2.5% solution of sugar.
Snowcat [4.5K]

(i) We start by calculating the mass of sugar in the solution:

mass of sugar = concentration × solution mass

mass of sugar = 2.5/100 × 500 = 12.5 g  

Then now we can calculate the amount of water:

solution mass = mass of sugar + mass of water

mass of water =  solution mass - mass of sugar

mass of water = 500 - 12.5 = 487.5 g

(ii) We use the following reasoning:

If       500 g solution contains 12.5 g sugar

Then    X g solution contains 75 g sugar

X=(500×75)/12.5 = 3000 g solution

Now to get the amount of solution in liters we use density (we assume that is equal to 1):

Density = mass / volume

Volume = mass / density

Volume = 3000 / 1 = 3000 liters of sugar solution

8 0
2 years ago
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