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adell [148]
3 years ago
5

Nitrogen combines with oxygen to form nitrogen monoxide (no) and nitrogen dioxide (no2). a sample of no consists of 1.14 g of ox

ygen and 1 g of nitrogen. how many grams of oxygen combine with 1 g of nitrogen to form no2if the ratio of the masses of oxygen in these two compounds is exactly 1:2?
Chemistry
2 answers:
frez [133]3 years ago
6 0

<u>Answer:</u> The mass of oxygen that combines with nitrogen will be 2.272g.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}   .....(1)

<u>For Oxygen atom:</u>

Given mass of oxygen atom = 1.14 g

Molar mass of oxygen atom = 16 g/mol

Putting values in above equation, we get:

\text{Moles of oxygen atom}=\frac{1.14g}{16g/mol}=0.071mol

<u>For Nitrogen atom:</u>

Given mass of nitrogen atom = 1 g

Molar mass of nitrogen atom = 14 g/mol

Putting values in above equation, we get:

\text{Moles of nitrogen atom}=\frac{1g}{14g/mol}=0.071mol

For the given chemical reaction:

2N_2+3O_2\rightarrow 2NO+2NO_2

In 1 mole of nitrogen dioxide molecule, 1 mole of nitrogen atom combines with 2 moles of oxygen atom.

So, 0.071 moles of nitrogen will combine with = \frac{2}{1}\times 0.071=0.142moles of oxygen atom.

Now, to calculate the mass of oxygen atom, we use equation 1:

0.142mol=\frac{\text{Mass of oxygen atom}}{16g/mol}\\\\\text{Mass of oxygen atom}=2.272g

Hence, the mass of oxygen that combines with nitrogen will be 2.272g.

Sever21 [200]3 years ago
4 0
2N2 + 3O2 ---> 2NO + 2NO2  
You should do it based on moles and not grams. 
1.14 g O = 0.071 moles O 
1 g N = 0.071 moles N  
So in NO2 you need 2 moles O for each mole of N 
1 g N = 0.071 moles, so you need 0.071 x 2 moles of O = 0.0.142 moles O 
0.142 moles O x 16 g/mol = 2.27 grams of O. So, you are actually correct because your answer is 2.28 grams. I just prefer to work it out in moles so it makes perfect chemical sense.
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Answer:

0.0344 moles and 1.93g.

Explanation:

Molarity is defined as the ratio between moles of a solute (In this case, KOH), and the volume. With molarity and volume we can solve the moles of solute. With moles of solute we can find mass of the solute as follows:

<em>Moles KOH:</em>

15.2mL = 0.0152L * (2.26mol / L) = 0.0344moles

<em>Mass KOH:</em>

0.0344 moles * (56.11g/mol) = 1.93g of KOH

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Explanation:

Ernest Rutherford performed the gold foil experiment in 1911 where he used alpha particles generated from a radioactive source to bombard a thin gold foil.

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Are alchemy and chemistry the same
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Are alchemy and chemistry the same: No

<u>Explanation:</u>

Alchemy and chemistry differ from each other. Their main difference lies in the concepts that they are based on. Alchemy has the base of viewing the reality of nature supernaturally. Chemistry has a base of viewing the reality in a natural way.

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At 850 K, the equilibrium constant for the reaction
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Answer:

Answers are in the explanation.

Explanation:

<em>Given concentrations are:</em>

  • <em>SO₂ = 0.20M O₂ = 0.60M SO₃ = 0.60M</em>
  • <em>SO₂ = 0.14M O₂ = 0.10M SO₃ = 0.40M </em>
  • <em>And SO₂ = 0.90M O₂ = 0.50M SO₃ = 0.10M</em>

<em />

In the reaction:

2SO₂(g) + O₂(g) ⇄ 2SO₃(g)

Kc is defined as:

Kc = 15 = [SO₃]² / [O₂] [SO₂]²

<em>Where concentrations of each species are equilbrium concentrations.</em>

<em />

Also, you can define Q (Reaction quotient) as:

Q = [SO₃]² / [O₂] [SO₂]²

<em>Where concentrations of each species are ACTUAL concentrations.</em>

<em />

If Q > Kc, the reaction will shift to the left until Q = Kc;

If Q < Kc, the reaction will shift to the right until Q = Kc

If Q = Kc, there is no net reaction because reaction would be en equilibrium.

Replacing with given concentrations:

  • Q = [0.60M]² / [0.60M] [0.20M]² = 15; Q = Kc → No net reaction
  • Q = [0.40M]² / [0.10M] [0.14M]² = 82; Q > Kc, → Reaction will shift to the left
  • Q = [0.10M]² / [0.50M] [0.90M]² = 0.015; Q < Kc → Reaction will shift to the right

<em />

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