All categories

3 years ago

In the following reaction, which compounds are considered based? HNO2+H2O <—>H3O + NO2

Chemistry

1 answer:

ehidna [41]3 years ago

7 0

Answer:

non of them are considered base hno3 is acidic ,H2O is neutral ,h30 is acidic likewise n02

You might be interested in

The metric system is only used in France? True or false

Olegator [25]

False it’s used in a lot of other countries

8 0

4 years ago

Read 2 more answers

I will give you 100 points and mark you as brainilest if you answer the whole thing correctly.

Nookie1986 [14]

Answer:

1.) $Al_{2} O_{3}$

2.) $Li_{3} N\\$

3.) 2HCl

4.) MgO

5.) Mg and $O_{2}$

6.) $H_{2}$ and $O_{2}$

7.)Na and $Br_{2}$

8.) 3 aluminums and 3 chlorides

Explanation:

6 0

3 years ago

How many lithium ions are present in 30.0 ml of 0.600 m li2co3 solution?

Nikolay [14]

First; use the relationship of molarity and moles/liter to find the moles of the solution.
so 0.600M ×0.030L = 0.018 moles
Then use the mole to mole ratio of lithium to lithium carbonate
0.18 × (2 Li ÷1 Li2CO3) = 0.036
and then multiply by Avogadro's number to find the ions of lithium
0.036 moles × (6.022×10^{23} ) = 2.167 ×10∧22 ions Li

4 0

3 years ago

Calculate ΔHo for the following reaction ussing the given bond dissociation energiesCH4(g) + 2O2(g) --> CO2(g) + 2H2O(g)BOND

Mazyrski [523]

Answer:

The ΔH° for the following reaction is -794 kJ, hence exothermic reaction,

Explanation:

$CH_4(g) + 2O_2(g)\rightarrow CO_2(g) + 2H_2O(g) ,$ ΔH° = ?

We are given with:

$\Delta H_{O-O}=142 kJ/mol$

$\Delta H_{O=O}=498 kJ/mol$

$\Delta H_{H-O}=459 kJ/mol$

$\Delta H_{C-H}=411 kJ/mol$

$\Delta H_{C-O}=358 kJ/mol$

$\Delta H_{C=O}=799 kJ/mol$

ΔH° =

(Energies required to break bonds on reactant side) - (Energies released on formation of bonds on product side)

$\Delta H^o=(1 mol\times 4\times \Delta H_{C-H}+2 mol\times 1\times \Delta H_{O=O})-(1 mol\times 2\times \Delta H_{C=O}+2 mol\times 2\times\Delta H_{H-O})$