1.1kg = 1100g
If each paper clip is 0.88g : 1100 / 0.88 = 1250
1250 paper clips in the box
Answer:
0.7457 g is the mass of the helium gas.
Explanation:
Given:
Pressure = 3.04 atm
Temperature = 25.0 °C
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T₁ = (25.0 + 273.15) K = 298.15 K
Volume = 1.50 L
Using ideal gas equation as:
![PV=nRT](https://tex.z-dn.net/?f=PV%3DnRT)
where,
P is the pressure
V is the volume
n is the number of moles
T is the temperature
R is Gas constant having value = 0.0821 L.atm/K.mol
Applying the equation as:
3.04 atm × 1.50 L = n × 0.0821 L.atm/K.mol × 298.15 K
<u>⇒n = 0.1863 moles</u>
Molar mass of helium = 4.0026 g/mol
The formula for the calculation of moles is shown below:
Thus,
![Mass_{He}= 0.7457\ g](https://tex.z-dn.net/?f=Mass_%7BHe%7D%3D%200.7457%5C%20g)
<u>0.7457 g is the mass of the helium gas. </u>
Answer:
4.62
so 5
the ratio is 2 na chlorates for 3 O2 so multiply 7 by 2/3
Explanation:
Answer:
true
Explanation:
you can't change it back, it's chemically changed