Question

If the nth term is , then the (n+1)st is: Please make sure you check the image :)

Answer 1

Answer:

$\large \boxed{\sf C. \ \frac{n+1}{2} (3n+2)}$

Step-by-step explanation:

$\displaystyle \frac{n}{2} (3n-1)$

To find the (n+1)st term, replace the n variable with n+1.

$\displaystyle \frac{n+1}{2} (3(n+1)-1)$

Expand brackets.

$\displaystyle \frac{n+1}{2} (3n+3-1)$

Subtract like terms in brackets.

$\displaystyle \frac{n+1}{2} (3n+2)$

Answer 2

Answer:

( n+1) /2 *( 3n+2)

Step-by-step explanation:

n/2 * ( 3n-1)

We want the n+1 term

Replace n with n+1

( n+1) /2 *( 3( n+1) -1)

Distribute

( n+1) /2 *( 3n+3 -1)

( n+1) /2 *( 3n+2)