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Helen [10]
3 years ago
10

Pilar wanted to use a estimation to solve a decimal addition problem. She correctly used estimation to rewrite the problem as 12

+ 3 + 5 + 6. What could her original problem have been
Mathematics
1 answer:
Maksim231197 [3]3 years ago
5 0

After estimation of decimals problem is written as

=12+3+5+6

There are infinite ways of writing the original problem, i am writing few ways

1. 12.10 +2.95+5.05+6.06----Rounding tenth and Hundreth to nearest ones that is a whole number.

2. 12.25+3.05+4.75+6.42----Rounding tenth and Hundreth to nearest ones that is a whole number.

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B) Write 25 x 10° in standard form.
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25 anything raised to zero equals one
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Determine the unit price of the candy using the graph below (I’m confused on this)
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Brand A costs $2 per ounce, B is $1, C is $0.50(?) I think
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Questions 16-17 | Math 1 - 0 points Solve the graph Help needed !!
iris [78.8K]

Answer:

16) The area of the circle is 25.1 units²

17) JKLM is a parallelogram but not a rectangle

Step-by-step explanation:

16) Lets talk about the area of the circle

- To find the area of the circle you must find the length of the radius

- In the problem you have the center of the circle and a point on

 the circle, so you can find the length of the radius by using the

 distance rule

* Lets solve the problem

∵ The center of the circle is (1 , 3)

∵ The point on the circle is (3 , 5)

- Using the rule of the distance between two points

* Lets revise it

- The distance between the two points (x1 , y1) and (x2 , y2) is:

 Distance = √[(x2 - x1)² + (y2 - y1)²]

∴ r = √[(3 - 1)² + (5 - 3)²] = √[4 + 4] = √8 = 2√2 units

∵ The area of the circle = πr²

∴ The area of the circle = π (2√2)² = 8π = 25.1 units²

* The area of the circle is 25.1 units²

17) To prove a quadrilateral is a parallelogram, prove that every

     to sides are parallel or equal or the two diagonal bisect

     each other

* The parallelogram can be rectangle if two adjacent sides are

  perpendicular to each other (measure of angle between them is 90°)

 or its diagonals are equal in length

- The parallel lines have equal slopes, then to prove the

  quadrilateral is a parallelogram, we will find the slopes of

  each opposite sides

* Lets find from the graph the vertices of the quadrilateral

∵ J = (0 ,2) , K (2 , 5) , L (5 , 0) , M (3 , -3)

- The opposite sides are JK , ML and JM , KL

- The slope of any line passing through point (x1 , y1) and (x2 , y2) is

 m = (y2 - y1)/(x2 - x1)

∵ The slop of JK = (5 - 2)/(2 - 0) = 3/2 ⇒ (1)

∵ The slope of LM = (-3 - 0)/(3 - 5)= -3/-2 = 3/2 ⇒ (2)

- From (1) and (2)

∴ JK // LM

∵ The slope of KL = (0 - 5)/(5 - 2) = -5/3 ⇒ (3)

∵ The slope of JM = (-3 - 2)/(3 - 0)= -5/3 ⇒ (4)

- From (3) and (4)

∴ KL // JM

∵ Each two opposite sides are parallel in the quadrilateral JKLM

∴ It is a parallelogram

- The product of the slopes of the perpendicular line is -1

* lets check the slopes of two adjacent sides in the JKLM

∵ The slope of JK = 3/2 and the slope of KL = -5/3

∵ 3/2 × -5/3 = -5/2 ≠ -1

∴ JKLM is a parallelogram but not a rectangle

4 0
3 years ago
the price of an item has been reduced by 40% the original price was $15 what is the price of the item now​
harkovskaia [24]
This answer would be 21 because you’d just do 15 increased by 40% which gave me 21
3 0
3 years ago
The factorization below is missing two positive integers a and b. 6x^(3)+18x^(2)-240x=6x(x-a)(x+b) Factor the polynomial and the
Dvinal [7]

Answer:

a = 5

Step-by-step explanation:

Hello, please consider the following.

6x^3+18x^2-240x=6x(x^2+3x-40)\\\\\text{** The sum of the zeroes is -3=-8+5 and the product is -40=-8*5. **}\\\\\text{** So, we can factorise. **}\\\\6x^3+18x^2-240x=6x(x^2+3x-40)=6x(x^2+8x-5x-40)\\\\=6x(x(x+8)-5(x+8))\\\\\large \boxed{=6x(x+8)(x-5)}

So, a = 5.

Thank you.

7 0
3 years ago
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