3(x + 2) + 4x – 5 = 7(x + 1) – 6
Please help
2 answers:
Answer:
No Solution
Step-by-step explanation:
Step 1:
3 ( x + 2 ) + 4x - 5 = 7 ( x + 1 ) - 6
Step 2:
3x + 6 + 4x - 5 = 7x + 7 - 6
Step 3:
7x + 1 = 7x + 1
Answer:
No Solution
Hope This Helps :)
Answer:
Infinitely many solutions or 0=0
Step-by-step explanation:
3(x + 2) + 4x – 5 = 7(x + 1) – 6
First distribute the 3 and 7 within the parentheses
3x+6+4x-5=7x+7-6
Then collect like terms
7x+1=7x+1
and that will ultimately equal 0=0 or, infinitely many solutions
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