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2 years ago

3(x + 2) + 4x – 5 = 7(x + 1) – 6 Please help

Mathematics

2 answers:

NeTakaya2 years ago

8 0

Answer:

No Solution

Step-by-step explanation:

Step 1:

3 ( x + 2 ) + 4x - 5 = 7 ( x + 1 ) - 6

Step 2:

3x + 6 + 4x - 5 = 7x + 7 - 6

Step 3:

7x + 1 = 7x + 1

Answer:

No Solution

Hope This Helps :)

valentina_108 [34]2 years ago

8 0

Answer:

Infinitely many solutions or 0=0

Step-by-step explanation:

3(x + 2) + 4x – 5 = 7(x + 1) – 6

First distribute the 3 and 7 within the parentheses

3x+6+4x-5=7x+7-6

Then collect like terms

7x+1=7x+1

and that will ultimately equal 0=0 or, infinitely many solutions

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Svetllana [295]

${ \qquad\qquad\huge\underline{{\sf Answer}}}$

Let's solve ~

Calculate discriminant :

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$\qquad \sf \dashrightarrow \: discriminant = {b}^{2} - 4ac$

$\qquad \sf \dashrightarrow \: d = (6) {}^{2} - (4 \times 3 \times 1)$

$\qquad \sf \dashrightarrow \: d = 36 - 12$

$\qquad \sf \dashrightarrow \: d = 24$

$\qquad \sf \dashrightarrow \: \sqrt {d} = 2 \sqrt{6}$

Now, let's calculate it's roots ( x - intercepts )

$\qquad \sf \dashrightarrow \: x = \cfrac{ - b \pm \sqrt{d} }{2a}$

$\qquad \sf \dashrightarrow \: x = \cfrac{ - 6\pm 2 \sqrt{6} }{2 \times 3}$

$\qquad \sf \dashrightarrow \: x = \cfrac{ - 6\pm 2 \sqrt{6} }{6}$

So, the intercepts are :

$\qquad \sf \dashrightarrow \: x = \cfrac{ - 6 - 2 \sqrt{6} }{6}$

and

$\qquad \sf \dashrightarrow \: x = \cfrac{ - 6 + 2 \sqrt{6} }{6}$

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