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ANEK [815]
4 years ago
8

Tyler stands at rest on a skateboard. He has a mass of 120 kg. His friend (m = 60 kg) jumps into his arms at a speed of 2 m/s. I

f Tyler catches his friend, how fast will they move on the skateboard?
Physics
1 answer:
Andrews [41]4 years ago
5 0
Momentum question. This is an inelastic collision, so 

m1v1+m2v2=Vf(m1+m2)
Vf=(m1v1+m2v2)/(m1+m2)=[(120kg)(0m/s)+(60kg)(2m/s)] / (120kg+60kg)
Vf=120kg m/s  /   180kg
Vf=0.67m/s

0.67m/s
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Describe a simple experiment to verify the principle of moments
liubo4ka [24]
Use a ruler, a pivot, some weights. set the experiment by putting the pivot then a ruler on top of it finally put the wights on each end of the ruler
5 0
4 years ago
You are standing on a bathroom scale in an elevator in a tall building. Your mass is
Oksanka [162]

Answer:

94 kg or 921.6 N

Explanation:

The velocity function is v(t) = 3t + 0.2t^2. The acceleration function, a(t), is the time derivative of the velocity function.

a(t) = \dfrac{d}{dt}v(t) = 3 + 0.4t

At t=4,

a(4) = 3 + 0.4\times4 = 3+1.6 =4.6\text{ m/s}{}^2

Because the elevator is going upwards, the net acceleration, a_N = g + a(4) where g us acceleration of gravity.

a_N = 9.8 + 4.6 = 14.4\text{ m/s}{}^2

The resultant weight is

W =m a_N =64\times14.4=921.6 \text{ N}

Since the bathroom scale is graduated in kg, it's reading is

m =\dfrac{W}{g}=\dfrac{921.6}{9.8}=94\text{ kg}

3 0
3 years ago
Which characteristic does inertia describe
nadezda [96]

Answer:

Inertia is the resistance of any physical object to any change in its velocity. This includes changes to the object's speed, or direction of motion. An aspect of this property is the tendency of objects to keep moving in a straight line at a constant speed, when no forces act upon them.

Explanation:

mark me brainlist if i help

3 0
3 years ago
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What type of lamp is used in a spectrophotometer to produce visible light?
avanturin [10]

Answer:

Visible, or infrared lights

3 0
3 years ago
Can someone plz help me with this I’m not understanding it and show work plz plz
Triss [41]

There are two forces acting on the teacher:

Force due to weight/gravity (Fg)

Force due to drag (Fd), which is a resistance opposite to the direction of motion. Think of an airplane flying through the sky: there will be air that tries to oppose the plane's direction of motion AKA air-resistance.

The force of gravity is always downward (the direction of gravity).

Like we said before, the force of drag is always opposite to the direction of motion. Since the teacher is falling down, the force of drag is exerted upward.

Look at the attached diagram. The teacher is the circle in the middle. The two arrows indicate the two forces and their directions.

Now let's look at numbers:

Fg = mg = 65kg * 9.81 m/s^2 = ??N

Fd = 320N

To find the "Net Force" we must add up all of the forces exerted on the teacher, BUT we have to take into account the direction of forces.

Let's define downward as our "positive" direction. Since downward is positive, that means our force due to gravity is positive = +Fg

But since our force due to drag is UPWARD that means our force is NEGATIVE = -Fd.

So our total net force is

\Sigma F = F_g - F_d

3 0
4 years ago
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