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4 years ago

11

A. Shape the pot so that it has a wider base and the same size rim.

1 answer:

elixir [45]4 years ago

7 0

Answer:

Answer =

Explanation:

Option A

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a 2.0*10^3 kg car accelerates from rest under the actions of two forces. One is a forward force of 1140 N provided by traction b

BlackZzzverrR [31]

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.

<span>KE = 1/2mv^2 = (1/2)(2000)(2^2) = 4000 J This must equal the net work acting on the car. W=Fd The net force is 1140-950= 190N. so, d=W/F = 4000/190 = 21.05 m</span>

4 0

3 years ago

You're in a car that gets 28 miles per gallon of gas, driving it at a constant speed. If you took the gas from the car tank, and

Nataly [62]

Answer:

The diameter of the hose is 0.326 mm.

Explanation:

Given that,

Speed of car = 28 miles/galllon

We need to calculate the radius

The rate of flow of fluid is from the equation of continuity

$\dfrac{V}{t}=Av$

Where, A = area of cross sectional

$\dfrac{V}{t}=\pi r^2v$

We know that,

The velocity is the ratio of displacement of gas per unit time.

$\dfrac{V}{t}=\pi r^\dfrac{x}{t}$

$\dfrac{V}{x}=\pi r^2$

Put the value into the formula

$\dfrac{0.00378541}{28\times1609.34}=\pi r^2$

$r=\sqrt{\dfrac{0.00378541}{28\times1609.34\times\pi}}$

$r=1.63\times10^{-4}\ m$

We need to calculate the diameter of the hose

$d = 2r$

Put the value of r

$d=2\times1.63\times10^{-4}$

$d=0.326\ mm$

Hence, The diameter of the hose is 0.326 mm.

6 0

3 years ago

Name the type of component that has a greater resistance as the current through it increases

Gnesinka [82]

Answer:

filament bulb, filament lamp

Explanation:

4 0

3 years ago

To measure the amount of mass in an object, which piece of equipment would be used?

Vladimir79 [104]

Answer=Balance
Hope this helps

5 0

3 years ago

Read 2 more answers

A cylindrical wire made of an unknown alloy hangs from a support in the ceiling. You measure the relaxed length of the wire to b

IceJOKER [234]

Answer: hello some of your values are wrongly written hence I will resolve your question using the right values

answer:

stiffness = 1.09 * 10^-6 N/m

Explanation:

Given data:

Length ( l ) = 16 m

radius of wire ( r ) = 3.5 m

mass ( m ) = 5kg

<u>Distance stretched ( Δl ) = 4 * 10^-3 m </u> ( right value )

<u>average bond length ( between atoms ) = 2.3 * 10^-10 m </u>( right value)

first step : calculate the area

area ( A ) = πr^2 = π * ( 3.5)^2 = 38.48 m^2

γ = MgL / A Δl

= [ (5 * 9.81 * 16 ) / ( 38.48 * (4.3*10^-3) ) ]

= 784.8 / 0.165 = 4756.36 N/m^2

hence : stiffness = γ * bond length

= 4756.36 * 2.3 * 10^-10 = 1.09 * 10^-6 N/m

8 0

3 years ago