Answer:The hybridisation of C1 and C2 are sp3 and sp2 respectively.
Explanation:
Here the first carbon (C-1) formed four straight single bonds.
Linking to the electron theory (a fig.1 shown below) one electron from 2s orbital moves to the empty 2pz orbital.
The 2s and the three 2p orbitals hybridise and each orbital will be completed by one electron shared mutually with and from N, H, H, and the other C.
C-2 the second carbon has an sp2 because it forms a double bond with oxygen.
In the sp2 hybridisation the 2s orbital hybridises with only two 2p orbitals leaving the other 2p orbital unhybridised. The orbitals in sp2 is to be completed with one more electron each by sharing covalently with the C, O and the other O.
Note: The unhybridised p orbital is completed with the other shared electron of the oxygen. This forms the π bond in the carbon-oxygen double bond. (Fig 2. Shows the electronic arrangements.)
Protons:13
neutrons:14
electrons:10
Answer: This can be quickly solved with "traintracks"
Explanation:
You start w/ grams of water and want to find moles of oxygen gas produced.
So you want to Convert:
Grams of water -> moles of water -> moles of oxygen gas.
The two things you need to know to set up the tracks are:
1)Molar mass of water- H2O
Hydrogen - 1.008(x2)
Oxygen - 16.00
Water - 18.016
Answer:
The mass of water = 219.1 grams
Explanation:
Step 1: Data given
Mass of aluminium = 32.5 grams
specific heat capacity aluminium = 0.921 J/g°C
Temperature = 82.4 °C
Temperature of water = 22.3 °C
The final temperature = 24.2 °C
Step 2: Calculate the mass of water
Heat lost = heat gained
Qlost = -Qgained
Qaluminium = -Qwater
Q = m*c*ΔT
m(aluminium)*c(aluminium)*ΔT(aluminium) = -m(water)*c(water)*ΔT(water)
⇒with m(aluminium) = the mass of aluminium = 32.5 grams
⇒with c(aluminium) = the specific heat of aluminium = 0.921 J/g°C
⇒with ΔT(aluminium) = the change of temperature of aluminium = 24.2 °C - 82.4 °C = -58.2 °C
⇒with m(water) = the mass of water = TO BE DETERMINED
⇒with c(water) = 4.184 J/g°C
⇒with ΔT(water) = the change of temperature of water = 24.2 °C - 22.3 °C = 1.9 °C
32.5 * 0.921 * -58.2 = -m * 4.184 * 1.9
-1742.1 = -7.95m
m = 219.1 grams
The mass of water = 219.1 grams