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larisa86 [58]
3 years ago
9

M + e - M-1Is M oxidized or reduced?​

Chemistry
2 answers:
podryga [215]3 years ago
5 0

Answer:

It is reduced!!

Explanation:

bazaltina [42]3 years ago
3 0

Answer:

Reduced  

Explanation:

M + e⁻ ⟶ M⁻

Reduction is the gain of an electron.

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0.90 g of sodium hydroxide ( NaOH ) pellets are dissolved in water to make 3.0 L of solution. What is the pH of this solution
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Explanation:

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What is the atomic radius
dimaraw [331]

Answer:

The atomic radius of a chemical element is a measure of the size of its atoms, usually the mean or typical distance from the center of the nucleus to the boundary of the surrounding shells of electrons.

5 0
3 years ago
Are pure substances chemically combined​
dmitriy555 [2]

Pure substances can or can not be chemically combined.

Pure substances can be either elements or compounds, but not mixture. Mixture are different substances mixing together without being chemically combined, such as air, which is a mixture of oxygen, carbon dioxide, water etc. Mixture can be separated by physical methods, like filtration or decantation.

Meanwhile, elements are the substances that cannot be further separated by any means. No matter physical or chemical methods. Examples of elements are oxygen, hydrogen, neon and all the other ones from the periodic table. Compounds are basically elements joining together, but they’re chemically combined which means their electrons (kind of subatomic particle) are either shared or given away. These elements can only be separated by chemical methods like electrolysis or heating.

Therefore, as long as the substance cannot be separated by physical methods, it can be considered as a pure substance. We can now conclude that pure substance can be (element) or can not be (compound) chemically combined.

4 0
4 years ago
In the laboratory, a quantity of I2 was reacted with excess H2 to give 1.26 moles of HI. It is also known that the percent yield
Anon25 [30]

Answer:

1.008moles of iodine

Explanation:

Hello,

This question requires us to calculate the theoretical yield of I₂ or number of moles that reacted.

Percent yield = (actual yield / estimated yield) × 100

Actual yield = 1.2moles

Estimated yield = ?

Percentage yield = 84%

84 / 100 = 1.2 / x

Cross multiply and solve for x

100x = 84 × 1.2

100x = 100.8

x = 100.8/100

x = 1.008moles

1.008 moles of I₂ reacted in excess of H₂ to give 1.2 moles of HI

5 0
3 years ago
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