A 0.25 kg baseball is in contact with a bat for 0.0075 s and exerts a force of 18,500 N. What impulse is delivered to the ball?
2 answers:
Answer:
Impulse, J = 140 kg m/s
Explanation:
It is given that,
Mass of the baseball, m = 0.25 kg
Force exerted on the baseball, F = 18,500 N
Time of contact of baseball and bat is, t = 0.0075 s
We have to find the impulse delivered to the bat. Impulse is defined as the product of force and time. It is also equivalent to change in momentum.
So, J = F × t
J = 138.75 N-s
or
J = 140 kg m/s
Hence, this is the required solution.
You might be interested in
In order to solve the problem, it is necessary to apply the concepts related to the conservation of momentum, especially when there is an impact or the throwing of an object.
The equation that defines the linear moment is given by
where,
m=Total mass
Mass of Object
Velocity before throwing
Final Velocity
Velocity of Object
Our values are:
Solving to find the final speed, after throwing the object we have
We have three objects. For each object a launch is made so the final mass (denominator) will begin to be subtracted successively. In addition, during each new launch the initial speed will be given for each object thrown again.
That way during each section the equations should be modified depending on the previous one, let's start:
A)
B)
C)
Therefore the final velocity of astronaut is 3.63m/s