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Elina [12.6K]
3 years ago
6

How much work (in J) is done against the gravitational force on a 3.9 kg briefcase when it is carried from the ground floor to t

he roof of the Empire State Building, a vertical climb of 380 m?
Physics
1 answer:
katrin2010 [14]3 years ago
3 0

Answer:

W = 14523.6 J

Explanation:

Given,

Mass = 3.9 Kg

Vertical height , h = 380 m

Work done against gravitational force

W = m g h

g is acceleration due to gravity

W = 3.9 x 9.8 x 380

W = 14523.6 J

Hence, the work done by the gravitational force is equal to W = 14523.6 J

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You push on a 30 kg box with a force of 120 N. What is the acceleration of the box2​
kumpel [21]

Answer:

6

Explanation:

120/30=6

8 0
2 years ago
In a 100 mm diameter horizontal pipe, a venturimeter of 0.5 contraction ratio has been fitted. The head of water on the meter wh
horrorfan [7]

Answer:

the rate of flow = 29.28 ×10⁻³ m³/s or 0.029 m³/s

Explanation:

Given:

Diameter of the pipe = 100mm = 0.1m

Contraction ratio = 0.5

thus, diameter at the throat of venturimeter = 0.5×0.1m = 0.05m

The formula for discharge through a venturimeter is given as:

Q=C_d\frac{A_1A_2}{\sqrt{A_1^2-A_2^2}}\sqrt{2gh}

Where,

C_d is the coefficient of discharge = 0.97 (given)

A₁ = Area of the pipe

A₁ = \frac{\pi}{4}0.1^2 = 7.85\times 10^{-3}m^2

A₂ = Area at the throat

A₂ = \frac{\pi}{4}0.05^2 = 1.96\times 10^{-3}m^2

g = acceleration due to gravity = 9.8m/s²

Now,

The gauge pressure at throat = Absolute pressure - The atmospheric pressure

⇒The gauge pressure at throat = 2 - 10.3 = -8.3 m (Atmosphric pressure = 10.3 m of water)

Thus, the pressure difference at the throat and the pipe = 3- (-8.3) = 11.3m

Substituting the values in the discharge formula we get

Q=0.97\frac{7.85\times 10^{-3}\times 1.96\times 10^{-3}}{\sqrt{7.85\times 10^{-3}^2-1.96\times 10^{-3}^2}}\sqrt{2\times 9.8\times 11.3}

or

Q=\frac{0.97\times15.42\times 10^{-6}\times 14.88}{7.605\times 10^{-3}}

or

Q = 29.28 ×10⁻³ m³/s

Hence, the rate of flow = 29.28 ×10⁻³ m³/s or 0.029 m³/s

5 0
3 years ago
X(????) = 5.0???? 2 − 4.0???? 3 m.
Burka [1]

Answer:

JA

Explanation:

s of time, (b) the velocity and acceleration at t = 2.0 s, (c) the time at which the position is a maximum, (d) the time at which the velocity is zero, and (e) the maximum position. Assume all variable and constants are in SI units.

4 0
3 years ago
The average speed of an object which moves 100 m in 5 seconds is?
CaHeK987 [17]

Answer:

A car

Explanation:

A car can travel 100 m in 5 seconds

Hope this helps!

3 0
3 years ago
An airplane is seller rates down a runway at 3.10 M/S squared 441.5 seconds from rest until finally left off the ground ,what is
sineoko [7]

Answer:

302129m

Explanation:

Using s= ut + 1/2at²

But u= 0

So

S= 1/2(3.1)(441.5)²

=302129m

6 0
3 years ago
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