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Nonamiya [84]
3 years ago
6

Roll 1 Die 1000 times by pressing the "Roll 100 Sets" button ten times. Then do the same for Roll 3 Dice and Roll 12 Dice. Which

best describes the sampling distributions? All three sampling distributions appear to follow the normal distribution. From left to right, the sampling distributions begin normal but then become non-normal. From left to right, the sampling distributions begin non-normal but then become more normal. All three sampling distributions appear to follow non-normal distributions.
Mathematics
2 answers:
MAVERICK [17]3 years ago
8 0

Answer:

From left to right, the sampling distributions begin non-normal but then become more normal.

Step-by-step explanation:

If we refer back to our question, we are being told that:

Roll 1 Die 1000 times by pressing the "Roll 100 Sets" button ten times.

The same is done for Roll 3 Dice and Roll 12 Dice

i.e

Roll 3 Dice 1000 times by pressing the "Roll 100 Sets" button ten times.

Roll 12 Dice 1000 times by pressing the "Roll 100 Sets" button ten times.

From the knowledge of Central Limit Theorem (CLT), we understand that the sampling distribution of a given sample mean usually approaches a normal distribution  as the sample size gets larger.

Now, if we roll 1 Die 1000 times in which every sample has 100 observations.

If 3 Dice is rolled the same way; we have 3 × 100

If 12 Dice is rolled the same way; we have 12 × 100

This typically implies that the sample size gets increasing , thus the sampling distribution begins non-normal but then becomes more normal.

Rom4ik [11]3 years ago
6 0

Answer:

all three sampling distributions appear to follow the normal distribution

Step-by-step explanation:

Sampling distribtuions follow a normal distribution.

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Answer:

A

Step-by-step explanation:

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2 years ago
I don't understand how to do this problem.
Delicious77 [7]
Answers: 

x = 4
EF = 14
CF = 7
EC = 7

-------------------------------------------------------------
-------------------------------------------------------------

Work Shown:

C is the midpoint of segment EF. This means that EC = CF. In other words, the two pieces are congruent. 

Use substitution and solve for x
EC = CF
5x-13 = 3x-5
5x-13+13 = 3x-5+13
5x = 3x+8
5x-3x = 3x+8-3x
2x = 8
2x/2 = 8/2
x = 4

Now that we know that x = 4, we can use this to find EC and CF

Let's compute EC
EC = 5x - 13
EC = 5*x - 13
EC = 5*4 - 13 ... replace x with 4
EC = 20 - 13
EC = 7

Let's compute CF
CF = 3x - 5
CF = 3*x - 5
CF = 3*4 - 5 ... replace x with 4
CF = 12 - 5
CF = 7

As expected, EC = CF (both are 7 units long).

By the segment addition postulate, we can say EC+CF = EF

EC+CF = EF
EF = EC+CF
EF = 7+7
EF = 14
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Answer:

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Step-by-step explanation:

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