Answer:
Around 0.73% of adults in the USA have stage 2 high blood pressure
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 121 and standard deviation of 16.
This means that 
Around what percentage of adults in the USA have stage 2 high blood pressure
The proportion is 1 subtracted by the p-value of Z when X = 160. So



has a p-value of 0.9927.
1 - 0.9927 = 0.0073
0.0073*100% = 0.73%
Around 0.73% of adults in the USA have stage 2 high blood pressure
Answer:
To multiply Mixed Fractions:
convert to Improper Fractions.
Multiply the Fractions.
convert the result back to Mixed Fractions.
Step-by-step explanation:
Answer:
Step-by-step explanation:
From the information given,
Number of sample, n = 200
Probability of success, p = 43/100 = 0.43
q = 1 - p = 1 - 0.43
q = 0.57
For a confidence level of 95%, the corresponding z value is 1.96.
The formula for determining the error bound for the proportion is
z × √pq/n
= 1.96 ×√(0.43 × 0.57)/200
= 1.96 × 0.035 = 0.0686
The upper boundary of the population proportion is
0.43 + 0.0686 = 0.5
The lower boundary of the population proportion is
0.43 - 0.0686 = 0.4
The error in the solution is
phat = 0.43/200 = 0.00215
Also,
[-0.0043, 0.0086] is wrong
X + y = 33
x girls = y + 7
(y + 7) + y = 33
2y + 7 = 33
2y = 26
y = 13 guys
20 girls