Answer:
A. 16
Step-by-step explanation:
We can use a ratio to solve
4 bracelets x bracelets
----------------- = -------------
12 minutes 48 minutes
Using cross products
4 * 48 = 12x
192 = 12x
Divide by 12 on each side
192/12 =12x/12
16 =x
Remark
There's a lot you don't know here. Are DE and GF parallel? Is B a right angle? You can't assume that it is. The safest way to proceed is to give x in terms of 58 and B. You might get an answer that gives you something like 32 but I don't think you can say that unless you are told somewhere that ABC is a right angle triangle with the right angle at B.
So what to do.
<BAC = 58o That's because <BAC = <IAK They vertically opposite.
<ABC + <BAC + <ACB = 180o All triangles have 180o
<ACB = 180 - 58 - <ABC Solve for an unknown angle of a triangle.
<ACB = 122 - <ABC
x = <ACB Vertically opposite angles.
x = 122 - <ABC Answer It's 32 if ABC is a right angle.
For this, there is two rules. The common slope-intercept form is y=ax + b. For parallel, b can change, but a, or the slope, can't change. But for perpendicular, the a should be -1/a, where the answer for times the original equation, or a, and the second equation, or -1/a, is -1. To prove these two rules, you can graph it using random numbers but follow these two rules. if you have any part that don't understand for this answer, feel free to ask in the "Ask for details" section.
Answer:
Go to this site
https://www.slader.com/discussion/question/what-is-the-effect-in-the-time-required-to-solve-a-problem-when-you-double-the-size-of-the-input-fro/
there should the your answer
Step-by-step explanation:
Answer: The area of the triangle is 24 square inches
Step-by-step explanation:
Hi, since the 2 triangles form a parallelogram ( see attachment) we have the base and height of the triangles, we have to apply the next formula:
Area of a triangle; (base x height) /2
Replacing with the values:
A = (8x6 )/2
A = 48 /2
A = 24 square inches
The area of the triangle is 24 inches
Feel free to ask for more if needed or if you did not understand something.