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kykrilka [37]
3 years ago
12

It takes 70 inches of ribbon to make a bow and wrap the ribbon around a box. The bow takes 32 inches of ribbon. The width of the

box is 14 inches. What is the height of the box
Mathematics
1 answer:
Westkost [7]3 years ago
7 0
You need two sides so you can rewrite it as:
2x = 70-(14+32)
2x = 24
x = 24/2
x = 12

The height is 12in.

Hope this helps! :)
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13,000 inches equals how many miles
Nataly [62]

Answer:

0.205177 mi

Step-by-step explanation:

Step 1: Find conversions

12 in = 1 ft

5280 ft = 1 mi

Step 2: Use Dimensional Analysis

13000 \hspace{2} in(\frac{1 \hspace{2} ft}{12 \hspace{2} in} )(\frac{1 \hspace{2} mi}{5280 \hspace{2} ft} )

0.205177 mi

8 0
3 years ago
Use the grouping method to factor x³ + x² + 3x+3.
Annette [7]

Answer:

D. (x + 1)(x^2 + 3)

Step-by-step explanation:

Hello!

We can group the first two terms and the last two terms.

<h3>Factor by Grouping</h3>
  • x^2 + x^2 + 3x + 3
  • x^2(x + 1) + 3(x + 1)
  • (x^2 + 3)(x + 1)

Factoring by grouping is the process of breaking down larger polynomials to smaller ones to factor. We can then combine like factors.

In the second step, we can see that we can rewrite x^3 + x^2 as x^2(x + 1), as both the two terms share a common factor of x^2. We can pull out x^2 from that expression. Similarly, 3x and 3 share a common factor of 3, so we can pull that out.

8 0
2 years ago
What is −5/6÷9/10 ?<br><br> A −27/25<br><br> B −4/3<br><br> C −25/27<br><br> D −3/4
Anna [14]

Answer and Step-by-step explanation:

\huge\boxed{~~Answer:\frac{-25}{27} ~~}

\frac{-5}{6} ÷ \frac{9}{10}=\frac{-25}{27}

5 0
3 years ago
Read 2 more answers
[1x-6]&gt;1 what are the solutions
a_sh-v [17]

Answer:

x > 7

(I think this is Right but not sure yet )

3 0
3 years ago
point b on the ground is 5 cm from point E at the entrance to Ollie's house. He is 1.8 m tall and is standing at Point D, below
enot [183]

Point B on the ground is 5 cm from point E at the entrance to Ollie's house.

Ollie is at a distance of 2.45 m from the entrance to his house when he first activates the sensor.

The complete question is as follows:

Ollie has installed security lights on the side of his house that is activated by a  sensor. The sensor is located at point C directly above point D. The area covered by the sensor is shown by the shaded region enclosed by triangle ABC. The distance from A to B is 4.5 m, and the distance from B to C is 6m. Angle ACB is 15°.

The objective of this information is:

  • To find angle CAB and;
  • Find the distance Ollie is from the entrance to his house when he first activates the sensor.

The diagrammatic representation of the information given is shown in the image attached below.

Using  cosine rule to determine angle CAB, we have:

\mathbf{\dfrac{AB}{Sin \hat {ACB}} = \dfrac{BC}{Sin \hat {CAB}}= \dfrac{CA}{Sin \hat {ABC}}}

Here:

\mathbf{\dfrac{AB}{Sin \hat {ACB}} = \dfrac{BC}{Sin \hat {CAB}}}

\mathbf{\dfrac{4.5}{Sin \hat {15^0}} = \dfrac{6}{Sin \hat {CAB}}}

\mathbf{Sin \hat {CAB} = \dfrac{Sin 15 \times 6}{4.5}}

\mathbf{Sin \hat {CAB} = \dfrac{0.2588 \times 6}{4.5}}

\mathbf{Sin \hat {CAB} = 0.3451}

∠CAB = Sin⁻¹ (0.3451)

∠CAB = 20.19⁰

From the diagram attached;

  • assuming we have an imaginary position at the base of Ollie Standing point called point F when Ollie first activates the sensor;          

Then, we can say:

∠CBD = ∠GBF

∠GBF = (CAB + ACB)      

(because the exterior angles of a Δ is the sum of the two interior angles.

∠GBF = 15° + 20.19°

∠GBF = 35.19°

Using the trigonometric function for the tangent of an angle.

\mathbf{Tan \theta = \dfrac{GF}{BF}}

\mathbf{Tan \ 35.19  = \dfrac{1.8 \ m }{BF}}

\mathbf{BF  = \dfrac{1.8 \ m }{Tan \ 35.19}}

\mathbf{BF  = \dfrac{1.8 \ m }{0.7052}}

BF = 2.55 m

Finally, the distance of Ollie║FE║ from the entrance of his bouse is:

= 5 - 2.55 m

= 2.45 m

Therefore, we can conclude that Ollie is at a distance of 2.45 m from the entrance to his house when he first activates the sensor.

Learn more about exterior angles here:

8 0
3 years ago
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