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Archy [21]
3 years ago
9

Suppose you toss a coin 100 times and get 71 heads and 29 tails. Based on these​ results, what is the probability that the next

flip results in a head​?
Mathematics
1 answer:
murzikaleks [220]3 years ago
4 0

Answer:

0.71

Step-by-step explanation:

When a coin is tossed 100 times, it yields heads 71 times and tails 29 times.

So the probability of heads = Number of heads/Total number of tosses

= \[\frac{71}{100}\]

= \[0.71\]

Similarly, probability of tails = Number of tails/Total number of tosses

= \[\frac{29}{100}\]

= \[0.29\]

So the probability that the next flip results in a head = Probability of heads in the toss = 0.71

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Evaluate the expression when a=14 and b=6<br><br><br><br> −8ab= ?
Allisa [31]

Answer:

- 8ab \\  \\  - 8 \times 14 \times 6 \\  \\  =  - 672

4 0
2 years ago
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How do i make 41/50 into 41/100
Simora [160]
You mutiply the 50 by 2 to get 100 but would change the 41 and multiply that by two and get 82/100
7 0
3 years ago
Suppose a triangle has two sides of length 33 amd 37, and that the angle between these two sides is 120°. What is the length of
jeka57 [31]

Answer:

c = 60.65 cm

Step-by-step explanation:

Given that,

The two sides of a triangle are 33 cm and 37 cm.

The angle between these two sides is 120°.

We need to find the length of the third side of the triangle. Let c is the third side. Using cosine rule,

c^2=a^2+b^2-2ab\cos C

a = 33 cm, b = 37 cm and C is 120°

So,

c^2=(33)^2+(37)^2-2\times 33\times 37\cos (120)\\\\c=60.65\ cm

So, the length of the third side of the triangle is 60.65 cm.

7 0
3 years ago
What is the discriminante of 9x^2+10x
Leni [432]
The discriminant of y=ax^2+bx+c is b^2-4ac

given
9x^2+10x+0
a=9
b=10
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6 0
3 years ago
Needdd hellpppppssssssss
Ratling [72]

Answer:

Choice number one:

\displaystyle \frac{5}{10}\cdot \frac{4}{9}.

Step-by-step explanation:

  • Let A be the event that the number on the first card is even.
  • Let B be the event that the number on the second card is even.

The question is asking for the possibility that event A and B happen at the same time. However, whether A occurs or not will influence the probability of B. In other words, A and B are not independent. The probability that both A and B occur needs to be found as the product of

  • the probability that event A occurs, and
  • the probability that event B occurs given that event A occurs.

5 out of the ten numbers are even. The probability that event A occurs is:

\displaystyle P(A) = \frac{5}{10}.

In case A occurs, there will only be four cards with even numbers out of the nine cards that are still in the bag. The conditional probability of getting a second card with an even number on it, given that the first card is even, will be:

\displaystyle P(B|A) = \frac{4}{9}.

The probability that both A and B occurs will be:

\displaystyle P(A \cap B) = P(B\cap A) =  P(A) \cdot P(B|A) = \frac{5}{10}\cdot \frac{4}{9}.

6 0
3 years ago
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