Answer:
There are 45 turns in the secondary coil.
Explanation:
Given that,
Input potential of the lamp, 
The output potential of the lamp, 
Number of turns in primary coil, 
We need to find the number of turns needed on the secondary coil. We know that the ratio for a transformer is as follows :
So, there are 45 turns in the secondary coil.
1. What is the force of the marble?
For an object near the surface of the earth, the gravitational force acting upon the object is given by:
F = mg
F is the gravitational force, m is the object's mass, and g is the acceleration of objects due to earth's gravity.
Given values:
m = 0.025kg, g = 9.8m/s²
Plug in the given values and solve for F:
F = 0.025×9.8
F = 0.25N
2. What is the marble's potential energy at the start of its fall?
The gravitational potential energy of an object near the earth's surface is given by:
PE = mgh
PE is the potential energy, m is the object's mass, g is the acceleration of objects due to earth's gravity, and h is the object's relative height.
new given values:
h = 0.08m
Since F = mg, you can simply multiply F×h to get PE. Use the result from question 1:
PE = F×h
PE = 0.25×0.08
PE = 0.02J
A.
It's has to do with the human body forming in the womb. It has a long explanation to it, but I hope just writing A helps.
Answer:
A. the magnitude of the force between the spheres is 3.97 x 10⁻⁴ N
B. the magnitude of its initial acceleration is 5.83 m/s²
Explanation:
given information:
metal sphere's mass, m = 0.1 g = 1 x 10⁻⁴ kg
charge, q = -21 nC = -2.1 x 10⁻⁸
r = 10 cm = 0.1 m
What is the magnitude of the force between the spheres?
F₁₂ = k q₁q₂/r²
= ( 9 x 10⁹) (-2.1 x 10⁻⁸)²/(0.1)²
= 3.97 x 10⁻⁴ N
If the upper sphere is released, it will begin to fall. What is the magnitude of its initial acceleration?
mg - F₁₂ = ma
a = g - (F₁₂/m)
= 9.8 - (3.97 x 10⁻⁴/1 x 10⁻⁴)
= 5.83 m/s²
To solve this problem it is necessary to take into account the concepts related to the magnetic moment and the torque applied over magnetic moments.
For the case of the magnetic moment of a loop we have to,
Where
I = Current
A = Area of the loop
Moreover the torque exerted by the magnetic field is defined as,
Where,
I = Current
A = Area of the loop
B = Magnetic Field
PART A) First we need to find the perimeter, then
The total Area of the loop would be given as,
Substituting at the equation of magnetic moment we have
Therefore the magnetic moment of the loop is 
PART B) Replacing our values at the equation of torque we have that
Therefore the torque exerted by the magnetic field is 
