if a water wave vibrates up and down 4 times each second,the distance between 2 successive crest is 5 meters, and the height fro
2 answers:
Answer:
4 Hz
5 m
1 m
20 m/s
Explanation:
The first part of the sentence describes the frequency of the wave i.e., the number of oscillations every second
f = 4 /s = 4 Hz
The second part of the sentence describes the wavelength or period of the wave i.e., the distance between successive crests or troughs.
λ = 5 m
The last part of the sentence describes the peak to peak amplitude of the wave i.e., the height between the lowest part to highest part of the wave
The peak amplitude is given by
The velocity of a wave is given by
v = fλ
⇒v = 4×5
⇒v = 20 m/s
The velocity of the wave is 20 m/s
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Answer:
E = 1580594.95 N/C
Explanation:
To find the electric field inside the the non-conducting shell for r=11.2cm you use the Gauss' law:
(1)
dS: differential of the Gaussian surface
Qin: charge inside the Gaussian surface
εo: dielectric permittivity of vacuum = 8.85 × 10-12 C2/N ∙ m2
The electric field is parallel to the dS vector. In this case you have the surface of a sphere, thus you have:
(2)
Qin is calculate by using the charge density:
(3)
Vin is the volume of the spherical shell enclosed by the surface. a is the inner radius.
The charge density is given by:
Next, you use the results of (3), (2) and (1):
Finally, you replace the values of all parameters, and for r = 11.2cm = 0.112m you obtain:
hence, the electric field is 1580594.95 N/C
Answer:
The answer is ""
Explanation:
apply the formula for calculating the average velocity to the relative air
Given value:
The final answer is "" in the south-east direction.