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Oliga [24]
3 years ago
11

How many liters of water vapor can be produced if 8.9 liters of methane gas (CH4) are combusted, if all measurements are taken a

t the same temperature and pressure? Show all of the work used to solve this problem.
CH4 (g) + 2 O2 (g) CO2 (g) + 2 H2O (g)
Chemistry
1 answer:
Burka [1]3 years ago
5 0
From the chemical equation given, one mole of CH4 yields two moles of water (H2O). If all the methane gas that is 8.9 L is combusted then the volume of water produced is the number of moles H2O times the volume of the methane gas used up, that is 8.9 L × 2 = 17.8 L of water produced. 


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