The climate defines the conditions, to start.
Certain plants will be associated with the climate and conditions.
There are techniques and tricks that may moderate the growing conditions and that may benefit certain plants.
528 calories or 2207.04 joules.
Q=MCT
Q=(6g)(1.0cal/g°C)(88°C)
Q= 528 calories
Q=MCT
Q=(6g)(4.18joules/g°C)(88°C)
Q= 2207.04 joules
Problem 57EDraw the Lewis structure for CO with an arrow representing the dipole moment. UseFigure 9.10 to estimate the percent ionic character of the CO bond. Step by step solutionStep 1 of 2Lewis structure of CO:Carbon has four valence electrons and oxygen has six valence electrons. If only one bond wereto be formed between carbon and oxygen atoms, carbon would have five electrons and oxygenwould have seven electrons.The single bond between these two atoms is not sufficient to lead to an octet on each atom . Tocomplete the octet of each atom in CO, we must employ a triple bond .A triple bond is formed bythe six electrons sharing between these two atoms and it is shown as follows.\nThe Lewis structure of CO with an arrow representing the dipole moment.The arrow towards anoxygen atom it represents is a highly electronegative atom.
The given data is as follows:
Element 1st IE
1 1310 kJ/mol
2 1011 kJ/mol
3 418 kJ/mol
4 2080 kJ/mol
5 947 kJ/mol
Ionization energy is the amount of energy required to remove an electron from an atom. It reflects the tendency of an atom to give away electrons readily. Lower the IE, more easily will the electron be lost. Low values of IE are characteristic of metals whereas, non-metals have higher IE values.
Based on the given data:
Element 4 is likely to be a non-metal
Element 3 is likely to be a metal