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Bess [88]
3 years ago
14

Which of the following devices can measure only atmospheric pressure? A. Pressure gauge B. Mercury tube C. Tire gauge D. Baromet

er
Chemistry
1 answer:
kap26 [50]3 years ago
4 0
D. Barometer. Hope this helps
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Here is my question only answer if you understand this question​
sasho [114]
1- false
2- true
3- true
4- false
5- true
6- false
7- true
8- true
9- true
10- false

Hope it helps :)
8 0
3 years ago
A student has 5 mL of 0.300 M (NH4)2CrO4 solution. What is the concentration of NH4+ in this solution?
mixer [17]
The answer is 0.600 M; but I don't know how to get to that answer.
4 0
3 years ago
Answer the following for the reaction: 3AgNO3(aq)+Na3PO4(aq)→Ag3PO4(s)+3NaNO3(aq)
Brums [2.3K]

Answer:1) Volume of AgNO_3 required is 55.98 mL.

2) 0.62577 grams of Ag_3PO_4 is produced.

Explanation:

3AgNO_3(aq)+Na_3PO_4(aq)\rightarrow Ag_3PO_4(s)+3NaNO_3(aq)

1) Molarity of AgNO_3,M_1=0.225 M

Volume of AgNO_3.V_1=?

Molarity of Na_3PO_4,M_2=0.135 M

Volume of Na_3PO_4,V_2=31.1 mL=0.0311 L

Molarity=\frac{\text{number of moles}}{\text{volume of solution in liters}}

\text{number of moles }Na_3PO_4=M_2\times V_2=0.135 mol/L\times 0.0311 L=0.0041985 moles

According to reaction, 1 mole of Na_3PO_4 reacts with 3 mole of AgNO_3, then, 0.0041985 moles of Na_3PO_4 will react with:

\frac{3}{1}\times 0.0041985 moles of AgNO_3 that is 0.0125955 moles.

M_1=0.225 M=\frac{\text{number of moles of }AgNO_3}{V_1}

V_1=\frac{0.0125955 moles}{0.225 M}=0.05598 L=55.98 mL

Volume of AgNO_3 required is 55.98 mL.

2)

Molarity=0.195 M=\frac{\text{number of moles}}{\text{volume of solution in liters}}

Number of moles of AgNO_3=0.195\times 0.023 L=0.004485 moles

According to reaction, 3 moles of AgNO_3 gives 1 mole of Ag_3PO_4, then 0.004485 moles of AgNO_3 will give:\frac{1}{3}\times 0.004485 moles of Ag_3PO_4 that is 0.001495 moles.

Mass of Ag_3PO_4 =

Moles of Ag_3PO_4 × Molar Mass of Ag_3PO_4

= 0.001495 moles × 418.58 g/mol = 0.62577 g

0.62577 grams of Ag_3PO_4 is produced.

7 0
3 years ago
This is the chemical formula for talc Mg3(Si2O5)2(OH)2(the main ingredient in talcum powder):
Elena-2011 [213]

Answer:

0.022 mol O

Explanation:

Mg3(Si2O5)2(OH)2

We can see that 1 mol of this substance has 3 mol of Mg.

Oxygen altogether  is 5*2 (from (Si2O5)2) + 2(from(OH)2) = 10 +2 = 12

So, 1 mol of this substance has 12 mol oxygen.

So,  1 mol of this substance contains 3 mol Mg and  12 mol O, or

ratio Mg : O = 3 : 12 = 1 : 4

1 mol Mg ----- 4 mol O

0.055 mol Mg ---x mol O

x = 0.055*4/1 = 0.220 mol O

8 0
3 years ago
Magnesium carbonate, MgCO3, reacts with nitric acid, HNO3, to form magnesium nitrate and carbonic acid. Carbonic acid reacts to
Karolina [17]
Carbonic acid undergoes decomposition reaction.  Decomposition reaction starts with one reactant and forms two or more products: AB⇒A+B. In this reaction, H2CO3 ⇒H2O + CO2.
8 0
3 years ago
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