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Nesterboy [21]
3 years ago
7

How many grams of iron (density = 7.87 g/mL ) would occupy the same volume as 96.4 g of aluminum (density = 2.70 g/mL)?

Chemistry
2 answers:
jasenka [17]3 years ago
7 0
Volume of Al:

D = m / V

2.70  =  96.4 / V

V = 96.4 / 2.70 => 35.70 mL

Mass of iron:

D = m / V

7.87 = m / 35.70

m = 7.87 x 35.70 => 280.959 g

hope this helps!
Helga [31]3 years ago
7 0

Answer:

280.9881 grams of iron.

Explanation:

In order to solve this we first have to calculate the volume of the aluminium because it is the one that we have all of the information to calculate:

Remember that the formula for density is:

Density=\frac{mass}{volume}

We clear it for volume and the result is:

Volume=\frac{Mass}{Density}

Now we just insert the values:

Volume=\frac{Mass}{Density}\\Volume=\frac{96,4g}{2,7}\\Volume= 35,70ml

Now that we have the volume we calculate how many grams of iron we need to occupy that volume, solving the formula for mas:

Volume=\frac{Mass}{Density}\\Mass=Volume*Density\\Mass= 35,70ml*7.87g/ml\\Mass=280.9881 ml

So the mass of iron needed to cover the same volume as 96.4 g of aluminium would be 280.9881 grams

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Svetlanka [38]

Answer:

It's b

Explanation:

I had the same exact question

5 0
2 years ago
32 g of sulfur will react with 48 g of oxygen to produce 80 g of sulfur trioxide. If 32 g of sulfur and 100 g of oxygen are plac
Lina20 [59]

Answer:

Since the container is consealed, and O2 will no be completely consumed, the total mass of material in the container will be 80 grams SO3+ 52 grams O2 = 132 grams (option B)

Explanation:

Step 1: Data given

Mass of sulfur = 32.00 grams

Mass of oxygen = 48.00 grams

Molar mass of sulfur = 32.07 g/mol

Molar mass of oxygen = 32 g/mol

Molar mass of SO3 = 80.07 g/mol

Step 2: The balanced equation

2S + 3O2 → 2SO3

Step 3: Calculate moles S

Moles S = Mass S / molar mass S

Moles S = 32.0 grams / 32.07 g/mol

Moles S = 0.998 moles

Step 4: Calculate moles O2

Moles O2 = 100.0 grams / 32.0 g/mol

Moles O2 = 3.125 moles

Step 5: Calculate the limiting reactant

For 2 moles S we need 3 moles O2 to produce 2 moles SO3

S is the limiting reactant. It will completely be consumed (0.998 moles)

O2 is in excess, there will be consumed 3/2 * 0.998 = 1.497 moles

There will remain 3.125- 1.497 = 1.628 moles O2

This is 1.628 moles * 32 g/mol = 52.1 grams

Step 6: Calculate moles SO3

For 2 moles S we need 3 moles O2 to produce 2 moles SO3

For 0.998 moles S there will react 0.998 moles SO3

Step 6: Calculate mass SO3

Mass SO3 = moles SO3 * molar mass SO3

Mass SO3 = 0.998 moles * 80.07 g/mol

Mass SO3 = 79.9 grams ≈ 80 grams

There will be produced 80 grams of SO3

Since the container is consealed, and O2 will no be completely consumed, the total mass of material in the container will be 80 grams SO3+ 52 grams O2 = 132 grams (option B)

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3 years ago
Calculate the molarity of a solution containing 5.6 mol of sodium hydroxide dissolved in 2.1 L of water
yKpoI14uk [10]

2.0 MOL is the correct answer I believe


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3 years ago
We know that organisms pass traits onto their offspring through reproduction. So how is it
Tpy6a [65]

Answer:

There are recessive traits and dominant traits

Explanation:

recessive traits are always hidden

dominant traits are the ones that are present in an organism

some recessive traits can be passed on to offsprings to become dominant

and some dominant traits can be passed on to become recessive traits

that's life

6 0
3 years ago
Read 2 more answers
Determine the full electron configurations:<br><br> 1. K+ (Z=19)<br><br> 2. Zn2+ (Z=30)
mixas84 [53]

Answer:

1=  K⁺= (Z=19) = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s⁰

2 = Zn²⁺= (Z = 30) =1s² 2s² 2p⁶ 3s² 3p⁶ 4s⁰, 3d¹⁰

Explanation:

When an atom lose or gain the electron ions are formed. There are two types of ions cation and anion.

Cation are formed when atom lose the electron.

Anion are formed when an atom gain the electron.

In given question potassium loses its valance electron and form K⁺ cation. Thus its electronic configuration will be written as,

₁₉K⁺ = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s⁰

While the electronic configuration of potassium in neutral form is:

₁₉K = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s¹

The atomic number of zinc is 30 and its electronic configuration is:

₃₀Zn= 1s² 2s² 2p⁶ 3s² 3p⁶ 4s², 3d¹⁰

When zinc atom loses its 2 valance electrons the electron configuration will be,

₃₀Zn²⁺= 1s² 2s² 2p⁶ 3s² 3p⁶ 4s⁰, 3d¹⁰

7 0
3 years ago
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