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3 years ago

5

How to write the ionic formula for the K1+, MnO41- pair of ions

1 answer:

Alja [10]3 years ago

5 0

Answer:

Ionic formula: KMnO4

Explanation:

Pottasium permanganate (KMnO4) is an ionic compound that contains a combination of pottasium cations (K+) and permanganate anion (MnO4-). The pair of ions that make up the ionic compound cancel out each other to make it neutral.

K+ (aq) + MnO4- (aq) → KMnO4 (aq)

MnO4- contains 1 atom of manganese with a (+7) charge and four atoms of oxygen with a (-2) charge each. This forms a +7 for Mn and -8 for O4, hence, a net total of -1.

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If 765 mL of a gas at 2.78 atm, has the volume Change to 2.47 L , What is the pressure of the

vampirchik [111]

Answer:

<h2>0.87 atm </h2>

Explanation:

The new pressure can be found by using the formula for Boyle's law which is

$P_1V_1 = P_2V_2$

Since we are finding the new pressure

$P_2 = \frac{P_1V_1}{V_2} \\$

From the question

2.47 L = 2470 mL

We have

$P_2 = \frac{765 \times 2.78}{2470} = \frac{2142}{2470} \\ = 0.867206...$

We have the final answer as

<h3>0.87 atm</h3>

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3 0

3 years ago

A compound is composed of only C, H, and O. The combustion of a 0.519-g sample of the compound yields 1.24 g of CO 2 and 0.255 g

vredina [299]

Answer:

$\large\boxed{\large\boxed{C_3H_3O}}$

Explanation:

<u>1. Calculate the mass of C in 1.24 g of CO₂</u>

$1.24gCO_2\times \dfrac{12.011gC}{44.01gCO_2}=0.3384gC$

<u>2. Calculate the mass of H in 0.255g of H₂O</u>

$0.255gH_2O\times \dfrac{2.016gH}{18.015gH_2O}=0.02854gH$

<u />

<u>3. Calculate the mass of O by difference</u>

$0.519g-0.3384g-0.02854g=0.15206g$

<u>4. Convert every mass to number of moles:</u>

C: 0.3384g / (12.011g/mol) = 0.02817 mol

H: 0.02854g / (1.008g/mol) = 0.02831 mol

O: 0.15206g / (15.999g/mol) = 0.009504 mol

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<u>5. Divide every number of moles by the least number of moles (0.009504):</u>

C: 0.02817/0.009504 = 2.96 ≈ 3

H: 0.02831 / 0.009504 ≈ 3

O: 0.009504 / 0.009504 = 1

<u>6. Those numbers are the respective subscripts in the empirical formula:</u>

$C_3H_3O$

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