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4 years ago

. Mitosis allows one cell to grow and split into 2 new cells. Will those 2 new cells split again explain.

Chemistry

1 answer:

Finger [1]4 years ago

4 0

Answer:

Yes

Explanation:

They continue to split and grow and split again until the organism that is carrying them dies.

Sorry I don't really know how to explain:(

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Which will have a greater volume: 10 grams of liquid water or 10 grams of solid water?

san4es73 [151]

The volume of 10 grams of frozen water is more than the volume of 10 grams of liquid water

5 0

3 years ago

When bethany walks across a carpet her socks pick up many electric charges. Later in the day these charges are no longer present

maxonik [38]

Answer:

When bethany walks across a carpet, her socks pick up many electric charges. Later in the day, these charges are no longer present on her socks. What most likely happened to the charges.

A. the charges disappeared.

B. The charges switched signs

C. the charges transferred to another object ✓

D. The charges broke apart into smaller particles

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3 years ago

Calculate the weight percent of ascorbic acid in a tablet of Vitamin C from the following data:A 80 mg sample of a crushed Vitam

Lina20 [59]

Answer:

The Answer is 88%

Explanation:

The balanced ionic equation of the reaction

$IO^{3- }+ 8 I^- + 6 H^+ => 3 I^{3- }+ 3 H_2O$

$I^{3-} + 2 S_2O_3^{2-} => 3 I^- + S_4O_6^{2-}$

$C_6H_8O_6 + I^{3- }+ H_2O => C_6H_6O_6 + 3 I^- + 2 H^+$

Looking at the above reactions

The original number of moles of $I^{3-}$ = 3 × number of moles of $IO^{3-}$

= 3 × volume × concentration of $KIO_3$

Note: The formula for number of moles is volume × concentration

$=3 * \frac{40}{1000} * 0.00653 =0.000784$ mol

The number of moles of $I^{3-}$ left after its reaction with ascorbic acid

= $\frac{1}{2}$ x moles of $S_2O_3^{2-}$

= $\frac{1}{2}$ x volume x concentration of $S_2O_3^{2-}$

$= \frac{1}{2} * \frac{15}{1000} * 0.0510 =0.000383 \ mol$

Note: The division by 1000 is to convert mill liter to liter

Moles of ascorbic acid = moles of $I^{3-}$ reacted

$= initial \ moles \ of \ I^{3-} \ - remaining \ moles \ of \ I^{3-}$

$=0.000784 - 0.000383$

$=0.000401 \ mols$

$Mass = moles \ * molar \ mass$

Hence

Mass of ascorbic acid = moles of ascorbic acid × molar mass of ascorbic acid

$= 0.000401* 176.12 = 0.07055\ g$

$= 70.55\ mg$

Weight% of ascorbic acid = mass of ascorbic acid/mass of sample x 100%

= 70.55/80 × 100%

= 88.1%

3 0

4 years ago

Combustion reaction all follow a similar pattern, complete the work equation below

ruslelena [56]

Hydrocarbon + Oxygen → Carbon dioxide + Water

6 0

3 years ago

A chemistry student needs 60.0 g of 2-ethyltoluene for an experiment. He has available 1.5 kg of a 15.3% w/w solution of 2 ethyl

Mila [183]

Answer:

392 g

Explanation:

The given concentration tells us that in 100 g of solution, there would be 15.3 g of 2-ethyltoluene.

With that in mind we can calculate how many grams of solution would contain 60.0 g of 2-ethyltoluene:

Mass of solution * 15.3 / 100 = 60.0 g 2-ethyltoluene

Mass of solution = 392 g

8 0

3 years ago