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2 years ago

Write the empirical formula for at least four ionic compounds that could be formed from the following ions

Chemistry

1 answer:

andreyandreev [35.5K]2 years ago

3 0

Answer:

NH₄CN, NH₄IO₃, Fe(CN)₃, Fe(IO₃)₃

Explanation:

Cations (positively charged ions) can only form ionic bonds with anions (negatively charged ions). However, you can't just simply put one cation and one anion together to form a compound. Each compound needs to been neutral, or have an overall charge of 0. When cations and anions do not have charges that perfectly cancel, you need to modify the amount of each ion in the compound.

1.) NH₄CN

-----> NH₄⁺ and CN⁻

-----> +1 + (-1) = 0

2.) NH₄IO₃

-----> NH₄⁺ and IO₃⁻

-----> +1 + (-1) = 0

3.) Fe(CN)₃

-----> Fe³⁺ and CN⁻

-----> +3 + (-1) + (-1) + (-1) = 0

4.) Fe(IO₃)₃

-----> Fe³⁺ and IO₃⁻

-----> +3 + (-1) + (-1) + (-1) = 0

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2 years ago

Read 2 more answers

An aqueous nacl solution is made using 112 g of nacl diluted to a total solution volume of 1.00 l. calculate the molarity, molal

worty [1.4K]

Q1)
molarity is defined as the number of moles of solute in 1 L of solution.
the NaCl solution volume is 1.00 L
number of moles NaCl = NaCl mass present / molar mass of NaCl
NaCl moles = 112 g / 58.5 g/mol = 1.91 mol
the number of moles of NaCl in 1.00 L of solution is - 1.91 mol
therefore molarity of NaCl is 1.91 M

Q2)
molality is defined as the number of moles of solute in 1 kg of solvent.
density is mass per volume.
density of the solution is 1.08 g/mL.
therefore mass of the solution is = density x volume
mass = 1.08 g/mL x 1000 mL = 1080 g
since we have to find the moles in 1 kg of solvent
mass of solvent = 1080 g - 112 g = 968 g
number of moles of NaCl in 968 g of solvent - 1.91 mol
therefore number of NaCl moles in 1000 g - (1.91 mol / 968 g) x 1000 g/kg = 1.97 mol/kg
molality of NaCl solution is 1.97 mol/kg

Q3)
mass percentage is the percentage of mass of solute by total mass of the solution
mass percentage of solution = mass of solute / total mass of the solution
mass of solute = 112 g
total mass of solution = 1080 g
mass % of NaCl = 112 g / 1080 g x 100%
therefore mass % of NaCl = 10.4 %
answer is 10.4 %

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3 years ago

Calculate the number of moles of Na+ ions in 25g of sodium carbonate?

valkas [14]

Explanation:

First, we need to calculate the number of moles of sodium carbonate we have in a 25 g sample. To calculate this, we will

find the molar mass of sodium carbonate (Na2CO3):

⇒ 2 × Molar mass of sodium + Molar mass of carbon + 3×molar mass of oxygen

⇒ 2 × 23 + 12 + 3 × 16

⇒ 46 + 12 + 48

⇒ 106g/mol

Thus, the molar mass of Na2CO3 is 106g/mol.

Therefore, number of moles = 25 ÷ 106

=> 0.2358 mol

Now, we know that every mole of Na2CO3 have 0.2358 moles of Na+ ions. Hence, total moles of Na2CO3 is 0.4716 moles

Number of ions present = 6.022 × 1023 × 0.4716 mol = 2.84 × 1023ions

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3 years ago

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gtnhenbr [62]

Answer: I believe the answer is an earthquake.

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3 years ago

Calculate the maximum concentration (in m) of silver ions (ag+) in a solution that contains 0.025 m of co32-. the ksp of ag2co3

Helen [10]

Equilibrium equation is

Ag2CO3(s) <---> 2 Ag+(aq) + CO32-(aq) 

From the reaction equation above, the formula for Ksp: 

Ksp = [Ag+]^2 [CO32-] = 8.1 x 10^-12 
You know [CO32-], so you can solve for [Ag+] as: 
(8.1 x 10^-12) = [Ag+]^2 (0.025) 
[Ag+]^2 = 3.24 x 10^-10 
[Ag+] = 1.8 x 10^-5 M

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3 years ago